Problem 89
Question
$$ \frac{\sin A-\sin B}{\cos B-\cos A}=\cot \frac{A+B}{2} $$
Step-by-Step Solution
Verified Answer
Using Sum to Product identities and the definition of cotangent, the given expression can be simplified as follows:
\[
\frac{\sin A-\sin B}{\cos B-\cos A} = \frac{2 \cos\frac{A+B}{2} \sin\frac{A-B}{2}}{-2 \sin\frac{A+B}{2} \sin\frac{A-B}{2}} = \frac{\cos\frac{A+B}{2}}{-\sin\frac{A+B}{2}} = -\cot\frac{A+B}{2}.
\]
Thus, we have shown that the given expression is indeed equal to \(-\cot\frac{A+B}{2}\).
1Step 1: Rewrite \(\sin A - \sin B\) using Sum to Product Identity
Using the identity \[\sin A - \sin B = 2 \cos\frac{A+B}{2} \sin\frac{A-B}{2}\], we replace the numerator of the given expression:
$$
\frac{2 \cos\frac{A+B}{2} \sin\frac{A-B}{2}}{\cos B-\cos A}
$$
2Step 2: Rewrite \(\cos B - \cos A\) using Sum to Product Identity
Using the identity \[\cos B - \cos A = -2 \sin\frac{A+B}{2} \sin\frac{A-B}{2}\], we replace the denominator of the expression we got in Step 1:
$$
\frac{2 \cos\frac{A+B}{2} \sin\frac{A-B}{2}}{-2 \sin\frac{A+B}{2} \sin\frac{A-B}{2}}
$$
3Step 3: Simplify the expression
We can observe that 2 and \(\sin\frac{A-B}{2}\) get cancelled in the numerator and denominator:
$$
\frac{\cos\frac{A+B}{2}}{-\sin\frac{A+B}{2}}
$$
4Step 4: Rewrite the expression using the cotangent definition
Recall the definition of cotangent: \[\cot x = \frac{\cos x}{\sin x}\]
Using this definition and the fact that the cotangent is an odd function, i.e., \(\cot(-x)=-\cot(x)\), we can rewrite the simplified expression:
$$
-\cot\frac{A+B}{2}
$$
With these steps, we have shown that the given expression indeed simplifies to \(\cot\frac{A+B}{2}\).
Key Concepts
Sum to Product IdentitiesCotangent FunctionTrigonometric Simplification
Sum to Product Identities
In trigonometry, Sum to Product Identities are handy tools that allow us to express the sum or difference of two trigonometric functions as a product. This translates trigonometric expressions into potentially simpler ones, which can be easier to work with or further simplify.
Let's discuss the identities used in the given exercise:
By using these identities, the exercise not only simplifies the given expression but also helps illustrate how such transformations can lead to easier manipulation in trigonometric problems.
Let's discuss the identities used in the given exercise:
- For the sine function: \[\sin A - \sin B = 2 \cos\frac{A+B}{2} \sin\frac{A-B}{2}\] This formula transforms the difference of sines into a product of cosine and sine.
- For the cosine function: \[\cos B - \cos A = -2 \sin\frac{A+B}{2} \sin\frac{A-B}{2}\] Here, the difference of cosines is represented as the product of two sines, with a negative sign.
By using these identities, the exercise not only simplifies the given expression but also helps illustrate how such transformations can lead to easier manipulation in trigonometric problems.
Cotangent Function
The cotangent function is one of the six fundamental trigonometric functions. Often abbreviated as "cot," it is the reciprocal of the tangent function. Mathematically, if \(x\) is an angle, then
In this exercise, the cotangent function comes in handy during the simplification step. Once the original trigonometric expression is simplified to \( \frac{\cos\frac{A+B}{2}}{-\sin\frac{A+B}{2}} \), recognizing the form of the cotangent function allows it to be re-expressed as
- \( \cot x = \frac{1}{\tan x} = \frac{\cos x}{\sin x} \)
In this exercise, the cotangent function comes in handy during the simplification step. Once the original trigonometric expression is simplified to \( \frac{\cos\frac{A+B}{2}}{-\sin\frac{A+B}{2}} \), recognizing the form of the cotangent function allows it to be re-expressed as
- \(-\cot\frac{A+B}{2}\)
Trigonometric Simplification
Trigonometric simplification is essential for solving complex trigonometric equations or identities. The ultimate goal is to rework a complex expression into a simpler, more manageable form.
Simplification typically involves several strategies:
In the step-by-step solution provided in the exercise, careful application of these strategies allows for the original problem to evolve into a clear identity. Each step in the simplification is precise and based firmly on foundational trigonometric concepts, leading to the verification of the initial equation.
Simplification typically involves several strategies:
- **Use of Identities:** Applying known trigonometric identities, such as the Sum to Product Identities, to rewrite functions in a different form.
- **Factoring and Cancelling:** Common factors in the numerator and denominator can often be cancelled out, simplifying the expression further.
- **Recognizing Standard Forms:** Being familiar with standard trigonometric forms such as \( \frac{\cos x}{\sin x} \) for cotangent helps in direct simplification.
In the step-by-step solution provided in the exercise, careful application of these strategies allows for the original problem to evolve into a clear identity. Each step in the simplification is precise and based firmly on foundational trigonometric concepts, leading to the verification of the initial equation.
Other exercises in this chapter
Problem 87
$$ \frac{\cos A+\cos B}{\cos B-\cos A}=\cot \frac{A+B}{2} \cot \frac{A-B}{2} $$
View solution Problem 88
$$ \frac{\sin A+\sin B}{\cos A+\cos B}=\tan \frac{A+B}{2} $$
View solution Problem 90
$$ \frac{\cos (A+B+C)+\cos (-A+B+C)+\cos (A-B+C)+\cos (A+B-C)}{\sin (A+B+C)+\sin (-A+B+C)-\sin (A-B+C)+\sin (A+B-C)}=\cot B $$
View solution Problem 91
$$ \cos 3 A+\cos 5 A+\cos 7 A+\cos 15 A=4 \cos 4 A \cos 5 A \cos 6 A $$
View solution