Problem 89
Question
Diamond has a density of \(3.513 \mathrm{g} / \mathrm{cm}^{3} .\) The mass of diamonds is often measured in "carats," where 1 carat equals \(0.200 \mathrm{g} .\) What is the volume (in cubic centimeters) of a 1.50 -carat diamond?
Step-by-Step Solution
Verified Answer
The volume of a 1.50-carat diamond is approximately 0.0854 cm³.
1Step 1: Convert carats to grams
First, convert the mass of the diamond from carats to grams. We know that 1 carat equals 0.200 grams. Therefore, for a 1.50-carat diamond, the mass will be: \ \[ 1.50 \text{ carats} \times 0.200 \text{ g/carats} = 0.300 \text{ g} \]
2Step 2: Use the density formula
To find the volume of the diamond, use the formula for density \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \). Rearrange it to solve for volume: \( \text{Volume} = \frac{\text{Mass}}{\text{Density}} \).
3Step 3: Substitute values into the volume formula
Substitute the mass of the diamond and the density into the formula. Given that the mass is 0.300 grams and the density is 3.513 g/cm³, we have: \[ \text{Volume} = \frac{0.300 \text{ g}}{3.513 \text{ g/cm}^3} \approx 0.0854 \text{ cm}^3 \]
Key Concepts
Volume CalculationMass ConversionDensity Formula
Volume Calculation
To determine the volume of an object, such as our diamond, we use the relationship between mass, volume, and density. The formula that connects these quantities is density
We know the mass (from the mass conversion explained later), and we know the density (as given in the exercise). All you need to do is plug these values into the formula, calculate, and hocus pocus! Volume appears. It’s as simple as that! Using the values 0.300 g for mass and 3.513 g/cm³ for density, the diamond's volume works out to approximately 0.0854 cm³.
This calculation demonstrates the beauty of these formulas and why they are so powerful in understanding physical characteristics.
- Density is defined as mass per unit volume.
- We can rewrite the density formula to solve for volume: \[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]
We know the mass (from the mass conversion explained later), and we know the density (as given in the exercise). All you need to do is plug these values into the formula, calculate, and hocus pocus! Volume appears. It’s as simple as that! Using the values 0.300 g for mass and 3.513 g/cm³ for density, the diamond's volume works out to approximately 0.0854 cm³.
This calculation demonstrates the beauty of these formulas and why they are so powerful in understanding physical characteristics.
Mass Conversion
Converting between units is an essential skill, especially when dealing with quantities that are not in standard units like grams or kilograms. In this case, the mass of diamond is given in carats.
To convert carats into grams, use:
Multiply the number of carats by the conversion factor (0.200 grams per carat):\[1.50 \text{ carats} \times 0.200 \text{ grams/carats} = 0.300 \text{ grams} \]
This conversion step is crucial because most density calculations use standard mass units like grams.
To convert carats into grams, use:
- 1 carat = 0.200 grams
Multiply the number of carats by the conversion factor (0.200 grams per carat):\[1.50 \text{ carats} \times 0.200 \text{ grams/carats} = 0.300 \text{ grams} \]
This conversion step is crucial because most density calculations use standard mass units like grams.
Density Formula
Understanding the density formula is key to solving problems involving material properties. The density of a material tells us how much mass is contained within a specific volume.
The basic density equation is:
For example, knowing the density of diamond as 3.513 g/cm³ helps us calculate the volume of a diamond when we know its mass (as we have calculated in grams).
By inserting our values into \( \text{Volume} = \frac{\text{Mass}}{\text{Density}} \), the real power of the density formula is revealed. With such a simple set of calculations, you are on your way to mastering densities!
The basic density equation is:
- \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \)
For example, knowing the density of diamond as 3.513 g/cm³ helps us calculate the volume of a diamond when we know its mass (as we have calculated in grams).
By inserting our values into \( \text{Volume} = \frac{\text{Mass}}{\text{Density}} \), the real power of the density formula is revealed. With such a simple set of calculations, you are on your way to mastering densities!
Other exercises in this chapter
Problem 87
Solve the following equation for the unknown value, \(T\) \((4.184)(244)(T-292.0)+(0.449)(88.5)(T-369.0)=0\)
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Solve the following equation for the unknown value, \(n\) $$ -246.0=1312\left[\frac{1}{2^{2}}-\frac{1}{n^{2}}\right] $$
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A The smallest repeating unit of a crystal of common salt is a cube (called a unit cell) with an edge length of \(0.563 \mathrm{nm}\). (a) What is the volume of
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An ancient gold coin is \(2.2 \mathrm{cm}\) in diameter and \(3.0 \mathrm{mm}\) thick. It is a cylinder for which volume = (\pi) (radius) \(^{2}\) (thickness).
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