Problem 88
Question
Use the quadratic formula to solve the equation. $$ 9 d^{2}-58 d+24=0 $$
Step-by-Step Solution
Verified Answer
The solutions to the equation \(9d^{2} - 58d + 24 = 0\) are \(d_1 = 6\) and \(d_2 = \frac{4}{9}\).
1Step 1: Identification of coefficients
In order to use the quadratic formula, first identify the coefficients \(a\), \(b\), and \(c\) in the given quadratic equation. For this equation \( 9d^{2} - 58d + 24 = 0 \), \(a\) is 9, \(b\) is -58, and \(c\) is 24.
2Step 2: Substitute the coefficients into the quadratic formula
Now substitute the coefficients into the quadratic formula, \(d = \frac{{-b \pm \sqrt{{b^{2}-4ac}}}}{{2a}}\), to get \(d = \frac{{58 \pm \sqrt{{(-58)^{2}-4*9*24}}}}{{2*9}} = \frac{{58 \pm \sqrt{{3364-864}}}}{{18}} = \frac{{58 \pm \sqrt{{2500}}}}{{18}}.\)
3Step 3: Solve the equation
Solve the equation to find the values of \(d\). This gives \(d = \frac{{58 \pm 50}}{{18}}\). So the two solutions are \(d_1 = \frac{{108}}{{18}} = 6\) and \(d_2 = \frac{{8}}{{18}} = \frac{{4}}{{9}}\).
Key Concepts
Solving Quadratic EquationsCoefficients in Quadratic EquationsSteps in Solving Quadratic Equations
Solving Quadratic Equations
To solve quadratic equations efficiently, one powerful method we use is the quadratic formula. This formula is particularly helpful when factoring is complex or impossible. Quadratic equations are of the form \( ax^2 + bx + c = 0 \), where \( a, b, \) and \( c \) are constants, with \( a eq 0 \). The quadratic formula provides the solutions to these equations directly. These solutions, also known as roots or zeros, can be calculated using:
- \( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \)
- If the discriminant is positive, two distinct real roots exist.
- If zero, one real root (a repeated root) exists.
- If negative, no real roots exist (the solutions are complex).
Coefficients in Quadratic Equations
In a quadratic equation, the coefficients \( a, b, \), and \( c \) play significant roles. Identifying them correctly is crucial for applying the quadratic formula. Let's break down these coefficients:
- \( a \): The coefficient of the quadratic term (\( x^2 \)). It determines the parabola's direction: upwards if \( a > 0 \) and downwards if \( a < 0 \).
- \( b \): The coefficient of the linear term (\( x \)). This affects the parabola's horizontal position on the graph.
- \( c \): The constant term. It indicates the parabola's vertical position or the y-intercept.
Steps in Solving Quadratic Equations
Solving a quadratic equation using the quadratic formula involves several key steps. Here they are explained in an approachable way:
Step 1: Identify Coefficients
Begin by recognizing the coefficients \( a \), \( b \), and \( c \) from the equation \( ax^2 + bx + c = 0 \). Replace these into the quadratic formula.Step 2: Apply the Quadratic Formula
Place these coefficients into the formula: \( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \). It's the heart of solving these equations. Calculate the discriminant, \( b^2 - 4ac \), first as it tells you the type of solutions you expect.Step 3: Solve for Roots
Complete the calculation to find the roots of the equation. Depending on the discriminant's value, you will find these roots:- Two solutions: \( x_1 \) and \( x_2 \) if the discriminant is positive.
- A single repeated solution if it's zero.
- Complex solutions if negative, although not applicable in this example.
Other exercises in this chapter
Problem 86
List all the factors of the number. 112
View solution Problem 87
Use the quadratic formula to solve the equation. $$ 9 x^{2}-14 x-7=0 $$
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$$ y>-2 x^{2}+4 x+16 $$
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Use the quadratic formula to solve the equation. $$ 7 y^{2}-9 y-17=0 $$
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