Problem 88
Question
The mineral rhodochrosite [manganese(II) carbonate, \(\left.\mathrm{MnCO}_{3}\right]\) is a commercially important source of manganese. How many moles of \(\mathrm{O}_{2}\) are consumed when one mole \(\mathrm{MnCO}_{3}\) is converted into \(\mathrm{MnO}_{2}\) and \(\mathrm{CO}_{2} ?\)
Step-by-Step Solution
Verified Answer
Answer: One mole of O2 is consumed.
1Step 1: Write a balanced chemical equation
First, we need to write the chemical reaction equation for the given process: the conversion of manganese(II) carbonate (MnCO3) into manganese dioxide (MnO2) and carbon dioxide (CO2). The unbalanced equation can be represented as:
MnCO3 + O2 → MnO2 + CO2
Now, we need to balance the equation by adjusting the number of atoms on each side. For this reaction, it is already a balanced equation, and no coefficients need to be adjusted.
2Step 2: Use stoichiometry to find the number of moles of O2 consumed
In order to determine the number of moles of O2 that are consumed in the reaction, we need to examine the stoichiometry of the balanced equation. The coefficients of the balanced equation represent the mole ratio of reactants and products:
1 MnCO3 + 1 O2 → 1 MnO2 + 1 CO2
This indicates that one mole of MnCO3 requires one mole of O2 to fully convert it into one mole of MnO2 and one mole of CO2. Therefore, when one mole of MnCO3 is converted, one mole of O2 is consumed.
Key Concepts
Balancing Chemical EquationsMole RatioChemical Reaction Equations
Balancing Chemical Equations
Balancing chemical equations is an essential skill in chemistry. It involves ensuring that the number of each type of atom is the same on both sides of a chemical reaction equation. This reflects the law of conservation of mass, which states that matter is neither created nor destroyed in a chemical reaction.
To balance a chemical equation, follow these steps:
To balance a chemical equation, follow these steps:
- Write down the unbalanced equation. For example, in converting manganese(II) carbonate to manganese dioxide and carbon dioxide, we start with: \( ext{MnCO}_3 + ext{O}_2 ightarrow ext{MnO}_2 + ext{CO}_2 \).
- Identify each type of atom present and count them on both sides of the equation.
- Add coefficients to balance each type of atom. The coefficients indicate the number of molecules or moles involved. Remember, you cannot change the subscripts in the chemical formulas as these define the substances.
Mole Ratio
The concept of mole ratio is pivotal in stoichiometry, and it is directly derived from a balanced equation. It allows us to predict the amounts of reactants needed and products formed in a chemical reaction.
In our example, the balanced equation shows that 1 mole of manganese carbonate ( \( ext{MnCO}_3 \) ) reacts with 1 mole of oxygen ( \( ext{O}_2 \) ) to produce 1 mole of manganese dioxide ( \( ext{MnO}_2 \) ) and 1 mole of carbon dioxide ( \( ext{CO}_2 \) ). This gives us a clear mole ratio:
In our example, the balanced equation shows that 1 mole of manganese carbonate ( \( ext{MnCO}_3 \) ) reacts with 1 mole of oxygen ( \( ext{O}_2 \) ) to produce 1 mole of manganese dioxide ( \( ext{MnO}_2 \) ) and 1 mole of carbon dioxide ( \( ext{CO}_2 \) ). This gives us a clear mole ratio:
- 1:1:1:1, which translates to 1 \( ext{MnCO}_3 \) : 1 \( ext{O}_2 \) : 1 \( ext{MnO}_2 \) : 1 \( ext{CO}_2 \).
Chemical Reaction Equations
Chemical reaction equations are symbolic representations that describe how substances transform during a chemical reaction. Understanding these equations helps to visualize the entire reaction process.
Every chemical equation needs three major components:
Every chemical equation needs three major components:
- Reactants: The starting materials that undergo change. In our exemplar equation, these are manganese carbonate ( \( ext{MnCO}_3 \) ) and oxygen ( \( ext{O}_2 \) ).
- Products: The substances that are produced as a result of the reaction. Here they are manganese dioxide ( \( ext{MnO}_2 \) ) and carbon dioxide ( \( ext{CO}_2 \) ).
- The "arrow" notation ( \( ightarrow \) ) separates reactants from products and indicates the direction of the chemical reaction.
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