Problem 88
Question
Factor each expression completely. $$ x^{2}-\frac{1}{25} $$
Step-by-Step Solution
Verified Answer
\((x + \frac{1}{5})(x - \frac{1}{5})\)
1Step 1: Identify the form of the expression
The given expression is \( x^2 - \frac{1}{25} \). This expression is in the form of a difference of squares, specifically \( a^2 - b^2 \), where \( a = x \) and \( b = \frac{1}{5} \) because \( (\frac{1}{5})^2 = \frac{1}{25} \).
2Step 2: Apply the difference of squares formula
The formula for the difference of squares is \( a^2 - b^2 = (a + b)(a - b) \). Using this formula, we substitute \( a = x \) and \( b = \frac{1}{5} \) into the equation.
3Step 3: Factor the expression
Applying the difference of squares formula gives us: \[ x^2 - \frac{1}{25} = \left(x + \frac{1}{5}\right)\left(x - \frac{1}{5}\right) \]. This is the completely factored form of the expression.
Key Concepts
Difference of SquaresAlgebraFactoring Techniques
Difference of Squares
The concept of difference of squares is a vital part of algebra, especially when it comes to factoring. This technique is applied when an expression has the structure of \( a^2 - b^2 \). Here, "difference" means subtraction, and "squares" means that both numbers are squared.
- The standard form of the difference of squares is \( a^2 - b^2 \) where \( a \) and \( b \) are any algebraic terms.
- This expression can be factored as \( (a + b)(a - b) \).
Algebra
Algebra is a branch of mathematics dealing with symbols and rules for manipulating these symbols. It includes everything from solving simple equations to complex polynomial expressions.
- Algebraic expressions are composed of variables, coefficients, and constants.
- Factoring is a key algebraic technique to simplify expressions and solve equations.
Factoring Techniques
Factoring is an essential algebraic technique used to break down or "factor" an expression into simpler terms or 'factors'. Various methods of factoring exist, each applicable to different types of expressions.
- The difference of squares technique is one of the simplest and most common methods, appropriate when the expression has the form \( a^2 - b^2 \).
- Other techniques include factoring by grouping and using the greatest common factor (GCF).
Other exercises in this chapter
Problem 87
Factor each trinomial completely. $$ z^{2}(x+1)-3 z(x+1)-70(x+1) $$
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See the Concept Check in this section. Do the terms of \(4 x^{2}+19 x+12\) have a common factor (other than 1\() ?\)
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Fill in the chart by finding two numbers that have the given product and sum. The first column is filled in for you. $$ \begin{array}{|l|c|c|c|c|c|c|c|c|} \hlin
View solution Problem 88
Factor each trinomial completely. $$ y^{2}(x+1)-2 y(x+1)-15(x+1) $$
View solution