Problem 88
Question
Evaluate the discriminant for each equation. Then use it to predict the number of distinct solutions, and whether they are rational, irrational, or non real complex. Do not solve the equation. $$2 x^{2}+4 x+1=0$$
Step-by-Step Solution
Verified Answer
The equation has two distinct irrational solutions.
1Step 1: Identify coefficients
Identify the coefficients from the quadratic equation. For the equation 2x^2 + 4x + 1 = 0: a = 2, b = 4, c = 1.
2Step 2: Calculate the discriminant
Use the formula for the discriminant, D = b^2 - 4ac. Substitute the values for a, b, and c: D = 4^2 - 4 * 2 * 1.
3Step 3: Simplify the discriminant
Simplify the equation to find the value of the discriminant: D = 16 - 8 = 8.
4Step 4: Analyze the discriminant
Evaluate the discriminant to predict the number and type of solutions: Since D = 8 > 0, the quadratic equation has two distinct real solutions. Moreover, since the discriminant is not a perfect square, the solutions are irrational.
Key Concepts
quadratic equationsdiscriminantreal solutionsirrational solutions
quadratic equations
A quadratic equation is a polynomial equation of the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants, and \(a eq 0\). This type of equation can describe a parabola in a graph and is fundamental in algebra. Quadratic equations can have different types of solutions, which we can predict using the discriminant. Let's explore how to do this in the context of the provided example: \(2x^2 + 4x + 1 = 0\).
discriminant
In the context of quadratic equations, the discriminant is a value that helps to determine the nature of the roots. It's calculated using the formula: \(D = b^2 - 4ac\). For the given equation (\(2x^2 + 4x + 1 = 0\)), we identify the coefficients as follows:
- \(a = 2\)
- \(b = 4\)
- \(c = 1\)
real solutions
Real solutions are the values for \(x\) that satisfy the quadratic equation and are real numbers, as opposed to imaginary or complex numbers. To determine the type of solutions, we can analyze the discriminant (\(D\)):
- If \(D > 0\), there are two distinct real solutions.
- If \(D = 0\), there is one real solution (a repeated root).
- If \(D < 0\), there are no real solutions; instead, there are two complex solutions.
irrational solutions
Irrational solutions are real numbers that cannot be expressed as a simple fraction. They are typically expressed in terms of square roots. When the discriminant is a positive number that is not a perfect square (like 8 in our example), the roots of the quadratic equation are irrational. For \(2x^2 + 4x + 1 = 0\), since \(D = 8\) is positive but not a perfect square, the equation has two distinct irrational solutions. Understanding these aspects helps us predict the nature of the solutions without actually solving the equation.
Other exercises in this chapter
Problem 88
Solve each rational inequality. Write each solution set in interval notation.4 $$\frac{9 x-8}{4 x^{2}+25}
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Solve each equation. $$7 x^{-2}-10 x^{-1}-8=0$$
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Simplify each power of i. $$i^{23}$$
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Suppose that \(y=5 x+1\) and we want \(y\) to be within 0.002 unit of \(6 .\) For what values of \(x\) will this be true?
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