Problem 88
Question
Draw the structures of the tripeptides gly-ala-ser and ser-alagly. How many other tripeptides are possible using these three amino acids?
Step-by-Step Solution
Verified Answer
The tripeptide Gly-Ala-Ser has the structure: H2N-CH2-CO-NH-CH(CH3)-CO-NH-CH(OH)-CH2-COOH, and the tripeptide Ser-Ala-Gly has the structure: H2N-CH(OH)-CH2-CO-NH-CH(CH3)-CO-NH-CH2-COOH. There are 4 other possible tripeptides using the three amino acids Gly (glycine), Ala (alanine), and Ser (serine).
1Step 1: Drawing the structure of Gly-Ala-Ser
First, we need to find the structure of each amino acid involved. Glycine (Gly) has the following structure: H2N-CH2-COOH, alanine (Ala) has the structure: H2N-CH(CH3)-COOH, and serine (Ser) has the structure: H2N-CH(OH)-CH2-COOH.
To construct the tripeptide Gly-Ala-Ser, we need to connect amino acids through peptide bonds. A peptide bond forms by the reaction of the carboxyl group (-COOH) of one amino acid with the amino group (-NH2) of another amino acid, releasing a water molecule.
The structure of Gly-Ala-Ser would be:
H2N-CH2-CO-NH-CH(CH3)-CO-NH-CH(OH)-CH2-COOH
2Step 2: Drawing the structure of Ser-Ala-Gly
Similarly, we can construct the tripeptide Ser-Ala-Gly by connecting serine, alanine, and glycine through peptide bonds.
The structure of Ser-Ala-Gly would be:
H2N-CH(OH)-CH2-CO-NH-CH(CH3)-CO-NH-CH2-COOH
3Step 3: Calculate the number of other possible tripeptides
Now, we need to determine the number of other possible tripeptides using these three amino acids. To do this, we can use the permutation formula. We have three unique amino acids, and we want to arrange them in three positions, which will be calculated as 3 × 2 × 1.
Number of other possible tripeptides = 3! = 3 × 2 × 1 = 6
However, we have already drawn two of these tripeptides (Gly-Ala-Ser and Ser-Ala-Gly), so the number of other possible tripeptides is:
6 - 2 = 4
So, there are 4 other possible tripeptides using the three amino acids Gly (glycine), Ala (alanine), and Ser (serine).
Other exercises in this chapter
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