Problem 88
Question
\(\bullet$$\bullet\) The monkey and her bananas. \(\Lambda 20 \mathrm{kg}\) monkey has a firm hold on a light rope that passes over a frictionless pulley and is attached to a 20 \(\mathrm{kg}\) bunch of bananas (Figure 5.72 ). The monkey looks up, sees the bananas, and starts to climb the rope to get them. (a) As the monkey climbs, do the bananas move up, move down, or remain at rest? (b) As the monkey climbs, does the distance between the monkey and the ba- nanas decrease, increase, or remain con- stant? (c) The monkey releases her hold on - the rope. What happens to the distance be- tween the monkey and the bananas while she is falling? (d) Before reaching the ground, the monkey grabs the rope to stop her fall. What do the bananas do?
Step-by-Step Solution
VerifiedKey Concepts
Newton's Laws
- **First Law (Inertia):** Objects at rest stay at rest, and objects in motion continue at constant speed in a straight line unless acted upon by an external force. When both the monkey and bananas are stationary, they remain so unless an external force, like the monkey climbing the rope, is applied.
- **Second Law (Acceleration):** An object’s acceleration is directly proportional to the net force acting on it and inversely proportional to its mass (\( F = ma \)). In this situation, when the monkey climbs the rope, there is no net force acting to create acceleration because the tension from both the monkey and bananas cancels each other out.
- **Third Law (Action-Reaction):** For every action, there is an equal and opposite reaction. When the monkey exerts a force climbing up, an equal force is exerted downward on the rope causing the bananas to exert force upward.
Frictionless Pulley
- **No Friction Influence:** There is no friction resisting the motion of the rope over the pulley. Thus, the force applied by the monkey is entirely transferred to the bananas.
- **Smooth Motion:** The absence of friction means any motion initiated by the monkey climbing does not affect the equilibrium of forces. It helps simplify calculations, making it easier to determine outcomes based on the forces present.
Equilibrium
- **Equal Masses:** Both the monkey and the bananas weigh 20 kg each, contributing equally to the tension force on either side of the rope.
- **Balance of Forces:** As the monkey climbs, the tension in the rope does not change sufficiently to create an imbalance, so the bananas remain stationary. The forces are entirely balanced, maintaining equilibrium.
Free Fall
- **Gravity's Role:** When the monkey lets go of the rope, both she and the bananas are solely under the influence of gravity. They fall together at the same acceleration, typically denoted as \(9.81 \, m/s^2\), maintaining the same distance apart.
- **Uniform Acceleration:** Free fall leads to a constant acceleration downwards for both objects, implying no differential motion between them. This explains why the gap between the monkey and the bananas stays unchanged during the fall.
Tension Forces
- **Equal Tension Distribution:** As both the monkey and bananas exert force, the tension remains uniform throughout the rope due to the equal weights on either side.
- **Impact of Actions:** When the monkey climbs, she changes the internal forces momentarily but the equal weights keep the system in balance. Tension is the reason why the bananas do not shift, even with her movements.
- **Tension Upon Halt:** When the monkey grabs the rope again to stop falling, the tension suddenly increases, causing the bananas to jerk upward momentarily.