Problem 88
Question
A motorcycle accelerates at a constant rate from 0 to \(50 \mathrm{mph}\) in \(15 \mathrm{sec} .\) How far does it travel during that time?
Step-by-Step Solution
Verified Answer
The motorcycle travels 550.125 feet during the 15 seconds.
1Step 1: Convert Speeds to Consistent Units
First, convert the speed from miles per hour (mph) to feet per second (ft/s) since time is given in seconds. The conversion factor is 1 mph = 1.467 ft/s. So, 50 mph is equivalent to \(50 \times 1.467 = 73.35 \text{ ft/s}\).
2Step 2: Calculate Average Speed
The initial speed is 0, and the final speed is 73.35 ft/s. The average speed during constant acceleration is given by the average of the initial and final speeds: \(\text{Average Speed} = \frac{0 + 73.35}{2} = 36.675 \text{ ft/s}\).
3Step 3: Calculate Distance Traveled
Using the formula for distance \(\text{Distance} = \text{Average Speed} \times \text{Time}\), and substituting the known values: \(\text{Distance} = 36.675 \text{ ft/s} \times 15 \text{ s} = 550.125 \text{ ft}\). Thus, the motorcycle travels 550.125 feet.
Key Concepts
Unit ConversionConstant AccelerationDistance Formula
Unit Conversion
Understanding unit conversion is vital in physics as it allows us to use consistent units across calculations. Imagine speaking a foreign language; unit conversion is like translating words into a language you understand. In the given exercise, speed was originally presented in miles per hour (mph), but the calculations required feet per second (ft/s). Thus, we needed to convert mph into ft/s.
This is done using a known conversion factor: 1 mph equals 1.467 ft/s. Knowing this, you can convert the final speed of the motorcycle by multiplying:
This is done using a known conversion factor: 1 mph equals 1.467 ft/s. Knowing this, you can convert the final speed of the motorcycle by multiplying:
- Convert 50 mph to ft/s by calculating: \[50 \times 1.467 = 73.35 \text{ ft/s}\]
Constant Acceleration
Constant acceleration is when an object's velocity changes at a steady rate over time. Think of it like a car steadily pressing the gas pedal, causing its speed to increase evenly rather than suddenly. In our motorcycle example, this means increasing speed from 0 mph to 50 mph at a consistent rate.
Because the acceleration is constant, it allows us to compute average speed in a straightforward way. The average speed is calculated by taking the mean of the initial speed and the final speed:
Because the acceleration is constant, it allows us to compute average speed in a straightforward way. The average speed is calculated by taking the mean of the initial speed and the final speed:
- Initial speed = 0 ft/s
- Final speed = 73.35 ft/s
- Average Speed = \(\frac{0 + 73.35}{2} = 36.675 \text{ ft/s}\)
Distance Formula
The distance formula is like a map guiding us to where an object goes globally. With the average speed known, we can now calculate the total distance the motorcycle travels during acceleration. The key formula here is:
- Distance = Average Speed \(\times\) Time
- Average Speed = 36.675 ft/s
- Time = 15 s
- Distance traveled = \(36.675 \text{ ft/s} \times 15 \text{ s} = 550.125 \text{ ft}\)
Other exercises in this chapter
Problem 87
A car accelerates at a constant rate from 0 to \(60 \mathrm{mph}\) in \(30 \mathrm{sec} .\) How far does the car travel during that time?
View solution Problem 88
Profit from marginal profit. A firm has the marginalprofit function $$ \frac{d P}{d x}=\frac{9000-3000 x}{\left(x^{2}-6 x+10\right)^{2}} $$ where \(P(x)\) is th
View solution Problem 89
Marriage rate. The marriage rate in the United States is approximated by $$ M(t)=8.3 e^{-0.019 t} $$ where \(M(t)\) is the number of marriages per 1000 people,
View solution Problem 89
A particle starts at the origin. Its velocity, in miles per hour, after \(t\) hours is given by $$v(t)=3 t^{2}+2 t$$ How far does it travel from the start of th
View solution