Problem 87
Question
Show that the graph of the equation \(r=2 a \cos \theta, a>0,\) is a circle of radius \(a\) with center \((a, 0)\) in rectangular coordinates.
Step-by-Step Solution
Verified Answer
The graph of the equation is a circle with center \((a, 0)\) and radius \(a\).
1Step 1: Write the given polar equation
Start with the given polar equation: \[ r = 2a \, \cos \theta \].
2Step 2: Use polar to rectangular coordinate conversion
Recall the conversions between polar and rectangular coordinates: \[ x = r \cos \theta \] and \[ y = r \sin \theta \]. We also have \[ r^2 = x^2 + y^2 \].
3Step 3: Multiply both sides by \( r \)
Multiply both sides of the equation \( r = 2a \cos \theta \) by \( r \): \[ r^2 = 2a r \cos \theta \].
4Step 4: Substitute rectangular coordinates expressions
Substitute \( r^2 = x^2 + y^2 \) and \( r \cos \theta = x \) into the equation: \[ x^2 + y^2 = 2ax \].
5Step 5: Rearrange the equation
Rearrange the equation to represent the standard form of a circle's equation: \[ x^2 - 2ax + y^2 = 0 \].
6Step 6: Complete the square
Complete the square for the \( x \)-terms: \[ (x - a)^2 - a^2 + y^2 = 0 \].
7Step 7: Simplify to the standard form of a circle
Add \( a^2 \) to both sides to isolate the squared term: \[ (x - a)^2 + y^2 = a^2 \]. This is the standard form of a circle's equation with center \((a, 0)\) and radius \(a\).
Key Concepts
polar coordinatesrectangular coordinatescircle equation
polar coordinates
Polar coordinates are a way to describe the position of a point in a plane using two values: the distance from a reference point (usually the origin) and the angle from a reference direction (usually the positive x-axis).
The coordinate pair \(r, \theta\) defines a point in the polar coordinate system.
Here, \(r\) is the radius or distance from the origin, and \(\theta\) is the angle measured in radians from the positive x-axis.
This system is particularly useful for problems featuring circular or spiral patterns and can make calculations simpler compared to Cartesian coordinates.
For example, the point with polar coordinates \(5, \pi/4\) is 5 units away from the origin, forming an angle of \(\pi/4\) radians with the x-axis.
The coordinate pair \(r, \theta\) defines a point in the polar coordinate system.
Here, \(r\) is the radius or distance from the origin, and \(\theta\) is the angle measured in radians from the positive x-axis.
This system is particularly useful for problems featuring circular or spiral patterns and can make calculations simpler compared to Cartesian coordinates.
For example, the point with polar coordinates \(5, \pi/4\) is 5 units away from the origin, forming an angle of \(\pi/4\) radians with the x-axis.
rectangular coordinates
Rectangular coordinates (or Cartesian coordinates) describe a point's position using two perpendicular axes: the x-axis and the y-axis.
A point on the plane is represented as \(x, y\), where \(x\) is the horizontal distance from the origin, and \(y\) is the vertical distance.
To convert from polar to rectangular coordinates, use the following relationships:
A point on the plane is represented as \(x, y\), where \(x\) is the horizontal distance from the origin, and \(y\) is the vertical distance.
To convert from polar to rectangular coordinates, use the following relationships:
- \(x = r \cos \theta \)
- \(y = r \sin \theta \)
- \(r = \sqrt{x^2 + y^2}\)
- \(\theta = \arctan \left( \frac{y}{x} \right)\)
circle equation
In rectangular coordinates, the standard equation for a circle centered at point \(h, k\) with a radius \(r\) is: \((x - h)^2 + (y - k)^2 = r^2\)
From this general form, you can see that the circle's center is \(h, k\), and its radius is \(r\).
To show that an equation represents a circle, you often need to manipulate the equation into this standard form.
In our solution, the given polar equation \(r = 2a \cos \theta\) was transformed into its rectangular equivalent.
By converting the polar equation to rectangular coordinates, we eventually arrived at the equation \((x - a)^2 + y^2 = a^2\).
This equation matches the standard form of a circle with center \(a, 0\) and radius \(a\), confirming that the graph is indeed a circle.
From this general form, you can see that the circle's center is \(h, k\), and its radius is \(r\).
To show that an equation represents a circle, you often need to manipulate the equation into this standard form.
In our solution, the given polar equation \(r = 2a \cos \theta\) was transformed into its rectangular equivalent.
By converting the polar equation to rectangular coordinates, we eventually arrived at the equation \((x - a)^2 + y^2 = a^2\).
This equation matches the standard form of a circle with center \(a, 0\) and radius \(a\), confirming that the graph is indeed a circle.
Other exercises in this chapter
Problem 87
A helicopter pilot needs to travel to a regional airport 25 miles away. She flies at an actual heading of \(\mathrm{N} 16.26^{\circ} \mathrm{E}\) with an airspe
View solution Problem 87
In Chicago, the road system is set up like a Cartesian plane, where streets are indicated by the number of blocks they are from Madison Street and State Street.
View solution Problem 88
Show that the graph of the equation \(r=-2 a \cos \theta, a>0\) is a circle of radius \(a\) with center \((-a, 0)\) in rectangular coordinates.
View solution Problem 89
At 10: 15 A.M., a radar station detects an aircraft at a point 80 miles away and 25 degrees north of due east. At 10: 25 A.M., the aircraft is 110 miles away an
View solution