Problem 87
Question
In factoring \(x^{2}+b x+c,\) describe how the last terms in each factor are related to \(b\) and \(c .\)
Step-by-Step Solution
Verified Answer
The last terms ( \(p\) and \(q\) ) in each factor of quadratic expression \(x^2 + bx + c\) relate to \(b\) and \(c\) respectively such that \(b = p + q\) (sum of \(p\) and \(q\)) and \(c = pq\) (product of \(p\) and \(q\)).
1Step 1: Recognize the Quadratic Form
The first step is recognizing the expression as a general form of a quadratic equation, \(x^2 + bx + c\). The values of \(b\) and \(c\) can impact the factors in a crucial manner.
2Step 2: Put in Factored Form
Assume that we factorize the quadratic equation into form, \(x^2 + bx + c = (x + p)(x + q)\). Here, \(p\) and \(q\) are the last terms in each factor.
3Step 3: Find Expression for \(p\) and \(q\)
By multiplying out these factors, we get \(x^2 + px + qx + pq\), which needs to be equivalent to \(x^2 + bx + c\). Comparing the like terms, we see \(b = p + q\) (the sum of \(p\) and \(q\)), and \(c = pq\) (the product of \(p\) and \(q\)).
Other exercises in this chapter
Problem 86
Factor completely. $$12 a^{2} b-34 a b^{2}+14 b^{3}$$
View solution Problem 87
Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$72 a^{3} b^{2}+12 a^{2}-24 a^{4} b^{2}$$
View solution Problem 87
Factor using the formula for the sum or difference of two cubes. $$x^{3} y^{3}-64$$
View solution Problem 87
Factor each polynomial. $$24 x^{3} y^{3} z^{3}+30 x^{2} y^{2} z+18 x^{2} y z^{2}$$
View solution