Problem 87
Question
Find the value of each of the following expressions. \(P=\frac{n(n-2)(n-4)}{2 n} . \quad\) Find \(P\) if \(n=-6\)
Step-by-Step Solution
Verified Answer
Answer: -40
1Step 1: Substitute the value of n in the expression
Substitute n = -6 in the expression \(P=\frac{n(n-2)(n-4)}{2 n}\).
\(P=\frac{-6(-6-2)(-6-4)}{2 (-6)}\)
2Step 2: Simplify the expression
Simplify the expression by calculating the values inside the parentheses.
\(P=\frac{-6(-8)(-10)}{2 (-6)}\)
3Step 3: Multiply the terms in the numerator and denominator
Calculate the numerator and denominator by multiplying the respective terms together.
\(P=\frac{480}{-12}\)
4Step 4: Divide the numerator by the denominator
Divide 480 by -12 to find the final value of P.
\(P=-40\)
Therefore, the value of \(P\) when \(n=-6\) is \(-40\).
Key Concepts
SubstitutionSimplifying ExpressionsNumerator and Denominator Manipulation
Substitution
Substitution is an important concept in algebra that involves replacing variables with numbers or other expressions. In our exercise, we substitute the given value of \(n = -6\) into the algebraic expression for \(P\): \(P=\frac{n(n-2)(n-4)}{2n}\).
Here’s how to do it step-by-step:
Here’s how to do it step-by-step:
- First, identify the variable in the expression, which is \(n\).
- Next, replace every instance of \(n\) in the expression with the number \(-6\).
- Your expression now looks like this: \(P=\frac{-6(-6-2)(-6-4)}{2(-6)}\).
Simplifying Expressions
Simplifying expressions is the process of transforming an expression into its simplest form. It often involves reducing the complexity while keeping the expression equivalent. Let's see how it’s done in our example.Firstly, once we substitute \(n = -6\), our expression becomes \(P=\frac{-6(-8)(-10)}{2 (-6)}\).
The task now is to simplify it:
The task now is to simplify it:
- Begin by performing operations inside the parentheses: \(-6-2 = -8\), and \(-6-4 = -10\).
- The expression then transforms to multiplied terms: \(-6\), \(-8\), and \(-10\).
Numerator and Denominator Manipulation
Manipulating the numerator and denominator is a crucial skill when working with fractions in algebra. This process involves performing operations to simplify the fraction's top (numerator) and bottom (denominator) parts separately, before combining them.In our original exercise:
- The numerator is \(-6 \times -8 \times -10\).
- The denominator is \(2 \times -6\).
- First, calculate the product of the numbers in the numerator: \(-6 \times -8 \times -10 = 480\).
- Next, calculate the product in the denominator: \(2 \times -6 = -12\).
Other exercises in this chapter
Problem 86
Find the product for the following problems. Write the result in scientific notation. $$ \left(9 \times 10^{-5}\right)\left(2 \times 10^{-1}\right) $$
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Write the following expressions using only positive exponents. Assume all variables are nonzero. $$ \frac{24 y^{2} z^{-8}}{6 a^{2} b^{-1} c^{-9} d^{3}} $$
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Find the product for the following problems. Write the result in scientific notation. $$ \left(3 \times 10^{-2}\right)\left(7 \times 10^{2}\right) $$
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Write the following expressions using only positive exponents. Assume all variables are nonzero. $$ \frac{3^{-1} b^{5}(b+7)^{-4}}{9^{-1} a^{-4}(a+7)^{2}} $$
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