Problem 87
Question
Find an equation of a parabola that satisfies the given conditions. Focus \((0,0) ;\) directrix \(x=-2\)
Step-by-Step Solution
Verified Answer
The equation of the parabola is \(y^2 = 4(x+1)\).
1Step 1: Understanding the Conditions
The focus of the parabola is given as \((0,0)\) and its directrix as \(x = -2\). Remember that a parabola is the set of all points equidistant from the focus and the directrix.
2Step 2: Using the Parabola Definition
The general equation for any parabola given a focus \((h,k)\) and a directrix \(x = d\) is \((y-k)^2 = 4p(x-h)\), where \(p\) is the distance from the vertex to the focus. Here, the focus \((0,0)\) and directrix \(x=-2\) imply the vertex is at \((-1,0)\) (midpoint).
3Step 3: Finding the Distance p
The distance \(p\) from the vertex \((-1,0)\) to the focus is 1, since \(0 - (-1) = 1\). Since the parabola opens to the right, \(p = 1\).
4Step 4: Forming the Parabola Equation
Substitute \(h = -1\), \(k = 0\), and \(p = 1\) into the parabola equation \((y-k)^2 = 4p(x-h)\). This becomes \(y^2 = 4(x+1)\).
Key Concepts
Focus and DirectrixParabola PropertiesConic Sections
Focus and Directrix
In the world of conic sections, a parabola stands out because of its unique structure defined by two key elements: the focus and the directrix. The focus is a fixed point inside the parabola, where all points on the curve are equally distant from this point and the directrix. The directrix, in contrast, is a straight line outside of the parabola.
Think of the focus and directrix as the parabolic GPS. They help us pinpoint the location of any point on the parabola. Here's a quick guide on how they work:
Think of the focus and directrix as the parabolic GPS. They help us pinpoint the location of any point on the parabola. Here's a quick guide on how they work:
- For any point on the parabola, the distance to the focus is the same as the distance to the directrix.
- The parabola is mostly symmetrical around a vertical or horizontal line, called the axis of symmetry, passing through the focus and perpendicular to the directrix.
Parabola Properties
Parabolas show distinctive properties based on their equation and orientation. A parabola can face upwards, downwards, or sideways. The orientation depends on the position of the focus and directrix. In mathematical terms, a parabola can be expressed in a standard equation form based on its particular properties.
When dealing with a focus at (0,0) and directrix as x = -2, as in this problem:
When dealing with a focus at (0,0) and directrix as x = -2, as in this problem:
- Since the directrix is vertical, the parabola is horizontal.
- The vertex, which is midway between the focus and directrix, is located at (-1,0).
- The parabola opens to the right because the focus is to the right of the directrix.
- The equation of this parabola can be expressed as (y-k)^2 = 4p(x-h), where (h,k) is the vertex.
Conic Sections
Conic sections are fascinating curves obtained by slicing a cone with a plane. Depending on the angle and position of this slice, we get different conic shapes like circles, ellipses, hyperbolas, and notably, parabolas.
Here’s why parabolas are intriguing as conic sections:
Here’s why parabolas are intriguing as conic sections:
- A parabola represents a special case where the slicing plane is parallel to another plane that is tangent to the cone.
- Every parabola is defined using a focus and directrix, making it distinctively Archimedean.
- Parabolas are common in physics and engineering, appearing in the paths of projectiles and the design of reflective surfaces.
Other exercises in this chapter
Problem 86
Find an equation of a parabola that satisfies the given conditions. Focus \((-1,2) ;\) vertex \((3,2)\)
View solution Problem 86
Graph the solution set of each system of inequalities by hand. $$\begin{aligned} &\frac{(x-2)^{2}}{36}+\frac{(y+2)^{2}}{25} \leq 1\\\ &\frac{(x+1)^{2}}{9}+\frac
View solution Problem 87
Solve each application. The orbit of Mars around the sun is an ellipse with equation $$\frac{x^{2}}{5013}+\frac{y^{2}}{4970}=1$$ where \(x\) and \(y\) are measu
View solution Problem 88
Find an equation of a parabola that satisfies the given conditions. Focus \((2,1) ;\) directrix \(x=-1\)
View solution