Problem 87
Question
Eric Daly has scores of \(75,83,\) and 85 on his history tests. Use an inequality to find the scores he can make on his final exam to receive a \(\mathrm{B}\) in the class. The final exam counts as two tests, and a \(\mathrm{B}\) is received if the final course average is greater than or equal to 80 .
Step-by-Step Solution
Verified Answer
Eric needs to score at least 79 on his final exam to maintain a B average.
1Step 1: Understand the problem
The problem requires finding the possible scores Eric can earn on his final exam to maintain a B average. The B average means his overall average should be at least 80, and the final exam counts twice.
2Step 2: Set up the total average formula
The average is calculated by dividing the total sum of scores by the number of tests. In this case, he has 3 test scores already, and the final counts as two, making a total of 5 test scores.
3Step 3: Express the inequality
Let the score on the final exam be represented by \( x \). The inequality for his average can be expressed as: \[ \frac{75 + 83 + 85 + 2x}{5} \geq 80 \]
4Step 4: Solve for \( x \)
Multiply both sides by 5 to clear the denominator: \[ 75 + 83 + 85 + 2x \geq 400 \] Combine the constants: \[ 243 + 2x \geq 400 \] Subtract 243 from both sides to isolate terms with \( x \): \[ 2x \geq 157 \] Finally, divide by 2: \[ x \geq 78.5 \]
5Step 5: Interpret the result
Since the score on a test must be a whole number, Eric must score at least 79 on his final exam to keep a B average.
Key Concepts
Final Exam Score CalculationB Average CalculationTest Score Inequality
Final Exam Score Calculation
To calculate what Eric needs on his final exam, we consider his past scores and how the final exam influences his overall grade. Eric's current scores are 75, 83, and 85. The key point to remember is that the final exam counts as two separate tests in his total average calculation.
With the final exam considered twice, his total number of scores becomes 5. This means that when we calculate the average, the final exam score will have a strong impact. Here's how you calculate the final test's contribution:
With the final exam considered twice, his total number of scores becomes 5. This means that when we calculate the average, the final exam score will have a strong impact. Here's how you calculate the final test's contribution:
- Add up all scores, including twice the final exam score.
- Divide by the total number of scores, which in this case is 5.
B Average Calculation
A 'B' average requires Eric’s total course average to be at least 80. Since the final exam counts as two tests, it's weighted heavily in achieving this target. To calculate whether he meets the 'B' threshold, we use Eric's previous test scores (75, 83, and 85) and project the impact of the final.
Steps to find out how he can achieve this average include:
Steps to find out how he can achieve this average include:
- Add current test scores (75, 83, 85)
- Include the final exam score twice in the calculation
- Divide by the total number of test scores, which is 5
Test Score Inequality
Test score inequalities are used to set conditions for grades. They help determine what score is needed on a remaining test—here, the final exam—to achieve a desired average. The challenge is to write an inequality that represents the needed condition. In this case, Eric wants to maintain a 'B' average, translating mathematically to the inequality:\[ \frac{75 + 83 + 85 + 2x}{5} \geq 80 \]This inequality is solved step by step:
- Clear fractions by multiplying both sides by 5: \( 243 + 2x \geq 400 \)
- Simplify to isolate terms with \( x \): \( 2x \geq 157 \)
- Divide to find \( x \): \( x \geq 78.5 \)
Other exercises in this chapter
Problem 86
Simplify each expression. See Section \(1.8 .\) \(-(3 a-3)+2 a-6\)
View solution Problem 86
A glacier is a giant mass of rocks and ice that flows downhill like a river. Exit Glacier, near Seward, Alaska, moves at a rate of 20 inches a day. Find the dis
View solution Problem 87
Solve. $$ 1000(7 x-10)=50(412+100 x) $$
View solution Problem 87
Simplify each expression. See Section \(1.8 .\) \(-(x-1)+x\)
View solution