Problem 86
Question
Will help you prepare for the material covered in the next section. If \(f(x)=2 x-5,\) find \(f^{-1}(x)\)
Step-by-Step Solution
Verified Answer
The inverse of the function \(f(x) = 2x - 5\) is \(f^{-1}(x) = (x+5)/2\).
1Step 1: Setup the Function
First, write down the given function \(f(x) = 2x - 5\). In order to find the inverse, we need to replace \(f(x)\) with \(y\), making the equation \(y = 2x - 5\).
2Step 2: Swap the Variables
The next step is to swap the variables x and y in the equation. This gives us \(x = 2y - 5\). This equation now represents the inverse function, but we still need to solve for y.
3Step 3: Solve for y
In order to solve for y, first add 5 to both sides of the equation: \(x + 5 = 2y\). Then, divide both sides by 2 to isolate y: \(y = (x+5)/2\).
4Step 4: Re-write the Inverse Function
The inverse function can now be written as \(f^{-1}(x) = (x+5)/2\) as a final step.
Key Concepts
Algebraic OperationsFunction NotationSolving Equations
Algebraic Operations
In the context of finding inverse functions, mastering algebraic operations is crucial. These operations, including addition, subtraction, multiplication, and division, are the building blocks for rearranging equations.
For example, to solve for the inverse of a function, we may need to add or subtract terms to isolate the desired variable. In the exercise given, we added 5 to both sides of the equation to isolate the term with the variable y. After that, noting that the y term was multiplied by 2, we divided the entire equation by 2 to solve for y.
Understanding these simple yet essential steps assists in manipulating equations to find the desired function or its inverse. As seen in the provided solution, by performing these operations systematically, we reached the expression of the inverse function.
For example, to solve for the inverse of a function, we may need to add or subtract terms to isolate the desired variable. In the exercise given, we added 5 to both sides of the equation to isolate the term with the variable y. After that, noting that the y term was multiplied by 2, we divided the entire equation by 2 to solve for y.
Understanding these simple yet essential steps assists in manipulating equations to find the desired function or its inverse. As seen in the provided solution, by performing these operations systematically, we reached the expression of the inverse function.
Function Notation
When dealing with functions, function notation provides a way to efficiently express relationships between variables. It's a shorthand that tells us which variable is independent (usually x) and which is dependent (often represented as f(x) or y).
Function notation comes in handy when finding inverses, as seen in the exercise. Initially, we start with a function named f with x as its input: f(x). When we find the inverse, we denote it as f⁻¹(x), read as 'f-inverse of x.' The purpose of function notation here is to clearly differentiate between the original function and its inverse. This notation is essential for clarity in communication and is commonly adopted in higher-level mathematics.
Function notation comes in handy when finding inverses, as seen in the exercise. Initially, we start with a function named f with x as its input: f(x). When we find the inverse, we denote it as f⁻¹(x), read as 'f-inverse of x.' The purpose of function notation here is to clearly differentiate between the original function and its inverse. This notation is essential for clarity in communication and is commonly adopted in higher-level mathematics.
Solving Equations
The process of solving equations is integral to find functions’ inverses. It involves re-arranging equations to find the value of an unknown variable. To solve the equation, we manipulate it using algebraic operations until the variable of interest stands alone on one side of the equation.
In our exercise, we took the original equation y = 2x - 5 and went through the steps of swapping the variables and then solving for y. This process required an understanding of how to correctly apply algebraic steps without altering the equation's integrity. The culmination of solving is to express the variable in its simplest form, which in the case of finding an inverse, provides us with f⁻¹(x), the inverse function notation.
In our exercise, we took the original equation y = 2x - 5 and went through the steps of swapping the variables and then solving for y. This process required an understanding of how to correctly apply algebraic steps without altering the equation's integrity. The culmination of solving is to express the variable in its simplest form, which in the case of finding an inverse, provides us with f⁻¹(x), the inverse function notation.
Other exercises in this chapter
Problem 86
Solve each logarithmic equation. Be sure to reject any value of \(x\) that is not in the domain of the original logarithmic expressions. Give the exact answer.
View solution Problem 86
Determine whether each equation is true or false. Where possible, show work to support your conclusion. If the statement is false, make the necessary change(s)
View solution Problem 87
The percentage of adult height attained by a girl who is \(x\) years old can be modeled by $$f(x)=62+35 \log (x-4)$$ where \(x\) represents the girl's age (from
View solution Problem 87
Solve each logarithmic equation. Be sure to reject any value of \(x\) that is not in the domain of the original logarithmic expressions. Give the exact answer.
View solution