Problem 86
Question
The price of a dress is reduced by \(40 \% .\) When the dress still does not sell, it is reduced by \(40 \%\) of the reduced price. If the price of the dress after both reductions is \(\$ 72,\) what was the original price?
Step-by-Step Solution
Verified Answer
The original price of the dress was \$200.
1Step 1: Define the Problem
In this case, we know the final price of the dress after two consecutive 40% reductions, and it is asked to find out the original price of the dress. Let's consider the original price to be \(x\). Then we can set up the relationship: \(0.6\times (0.6\times x) = 72\).
2Step 2: Solve the Equation
First, resolve the brackets in the equation by multiplying 0.6 and 0.6 to get \( 0.36x = 72\). To solve this for \(x\), divide both sides of the equation by 0.36 to get \(x = 72/0.36 \).
3Step 3: Calculate Original Price
After simplifying the equation in the previous step, it results in \(x = 200\). This means the original price of the dress was \$200.
Other exercises in this chapter
Problem 85
Solve each absolute value inequality. $$3 \leq|2 x-1|$$
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Evaluate \(x^{2}-x\) for the value of \(x\) satisfying \(4(x-2)+2=4 x-2(2-x)\).
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Solve each equation in Exercises \(83-108\) by the method of your choice. $$ 5 x^{2}=6-13 x $$
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Find all values of \(x\) satisfying the given conditions. $$y=|2-3 x| \text { and } y=13$$
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