Problem 86
Question
The molar concentration of \(20 \mathrm{~g}\) of \(\mathrm{NaOH}\) present in 5 litre of solution is (a) \(0.1 \mathrm{~mol} / \mathrm{L}\) (b) \(0.2 \mathrm{~mol} / \mathrm{L}\) (c) \(\mathrm{v} 1.0 \mathrm{~mol} / \mathrm{L}\) (d) \(2.0 \mathrm{~mol} / \mathrm{L}\)
Step-by-Step Solution
Verified Answer
The molar concentration is \(0.1 \text{ mol/L}\), option (a).
1Step 1: Calculate molar mass of NaOH
First, we need to determine the molar mass of sodium hydroxide (NaOH). The atomic mass of sodium (Na) is approximately 23 g/mol, oxygen (O) is 16 g/mol, and hydrogen (H) is 1 g/mol. Therefore, the molar mass of NaOH is calculated as follows: \(23 + 16 + 1 = 40 \text{ g/mol}\).
2Step 2: Calculate moles of NaOH
Next, we calculate the number of moles of NaOH using the formula \(\text{Number of moles} = \frac{\text{Mass of substance (g)}}{\text{Molar mass (g/mol)}}\). Substituting the given values, we have \(\frac{20 \text{ g}}{40 \text{ g/mol}} = 0.5 \text{ mol}\).
3Step 3: Calculate molar concentration
The molar concentration of a solution is given by \(\text{Molarity} = \frac{\text{Moles of solute}}{\text{Volume of solution (L)}}\). Here, the volume of the solution is given as 5 L. Therefore, substituting the values we found: \(\frac{0.5 \text{ mol}}{5 \text{ L}} = 0.1 \text{ mol/L}\).
Key Concepts
Molar MassNumber of MolesVolume of Solution
Molar Mass
Molar mass is essentially the mass of one mole of a substance. It's a pivotal concept in chemistry because it provides the bridge between the atom and the gram scale. For sodium hydroxide (NaOH), the molar mass is calculated by summing the atomic masses of each constituent element.
- Sodium (Na) has an atomic mass of about 23 g/mol.
- Oxygen (O) has an atomic mass of 16 g/mol.
- Hydrogen (H) has an atomic mass of approximately 1 g/mol.
Number of Moles
The number of moles is a measure of the quantity of a substance. Essentially, it tells us how many units (atoms, molecules, etc.) are present in a sample of matter. To find the number of moles, you divide the mass of the sample by its molar mass, using the formula:\[\text{Number of moles} = \frac{\text{Mass of the substance (g)}}{\text{Molar mass (g/mol)}}\]In our example, we have 20 grams of NaOH, and the molar mass is 40 g/mol. Therefore:\[\text{Number of moles} = \frac{20 \text{ g}}{40 \text{ g/mol}} = 0.5 \text{ mol}\]This tells us that in 20 grams of NaOH, there are 0.5 moles. Understanding this concept is crucial, as moles are a foundational unit in chemistry that allows us to relate masses to quantities of molecules or atoms.
Volume of Solution
The volume of the solution is important in calculating molarity, which is the measure of concentration in a solution. Molarity is expressed in moles per liter (mol/L), and it's necessary to use the volume of the solution in liters to calculate it correctly.
- The formula for molarity is:\[\text{Molarity} = \frac{\text{Moles of solute}}{\text{Volume of solution (L)}}\]
Other exercises in this chapter
Problem 84
How many grams of \(\mathrm{CH}_{3} \mathrm{OH}\) would have to be added to water to prepare \(150 \mathrm{~mL}\) of a solution that is \(2.0 \mathrm{M}\) \(\ma
View solution Problem 85
The oxide of an element contains \(67.67 \%\) of oxygen and the vapour density of its volatile chloride is 79 . Equivalent weight of the element is (a) \(2.46\)
View solution Problem 88
Maximum number of molecules will be in (a) \(1 \mathrm{~g}\) of \(\mathrm{H}_{2}\) (b) \(10 \mathrm{~g}\) of \(\mathrm{H}_{2}\) (c) \(22 \mathrm{~g}\) of \(\mat
View solution Problem 89
Haemoglobin contains \(0.33 \%\) of iron by weight. The molecular weight of haemoglobin is approximately 67200 . The number of iron atom (at. wt of \(\mathrm{Fe
View solution