Problem 86
Question
Solve the equation. Check the result. (Review 3.4 ) $$-6(q+22)=5 q$$
Step-by-Step Solution
Verified Answer
The solution to the equation is \( q = -12 \)
1Step 1: Distribute -6 Over the Parenthesis
Start by distributing the -6 over \( q+22 \) to get \( -6q - 132 = 5q \)
2Step 2: Rearrange Terms
Next, add \( 6q \) to both sides of the equation to collect all \( q \) terms on one side, this leads to: \( -132 = 5q + 6q \)
3Step 3: Simplify Terms
On the right side, combine like terms (5q + 6q) to get \( -132 = 11q \)
4Step 4: Solve For q
Finally, divide by 11 on both sides to isolate \( q \). This gives: \( q = -132/11 \)
5Step 5: Check the Solution
To check if our solution is correct, we substitute \( q = -12 \) back into the original equation: \( -6(-12+22) = 5(-12) \). Both sides evaluate to be -120, thus confirming \( q = -12 \) as the correct solution
Key Concepts
Distributive PropertyCombining Like TermsEquation CheckingIsolating Variables
Distributive Property
Understanding the distributive property is crucial to solving linear equations. It's a mathematical principle that allows us to remove parentheses by distributing a factor across each term inside the parenthesis. For example, with the equation \( -6(q+22) = 5q \), you apply the distributive property by multiplying \( -6 \) with both \( q \) and \( 22 \), leading to \( -6q - 132 \). This step is foundational to simplifying the equation and moving towards a solvable format.
Use the distributive property every time you notice parentheses combined with a numerical factor. This action simplifies your equation and prepares it for subsequent steps, like combining like terms and isolating the variable.
Use the distributive property every time you notice parentheses combined with a numerical factor. This action simplifies your equation and prepares it for subsequent steps, like combining like terms and isolating the variable.
Combining Like Terms
Once you've distributed your factors, the next step in resolving a linear equation is to combine like terms. Like terms are mathematical expressions that have the same variable raised to the same power. In our equation, \( 5q + 6q \) are like terms because they both contain the variable \( q \) raised to the first power.
By combining \( 5q \) and \( 6q \) together, we get \( 11q \), which significantly simplifies the equation. This step is critical because it consolidates the variable terms into a single term, making it easier to isolate the variable in subsequent steps.
By combining \( 5q \) and \( 6q \) together, we get \( 11q \), which significantly simplifies the equation. This step is critical because it consolidates the variable terms into a single term, making it easier to isolate the variable in subsequent steps.
Equation Checking
Verifying your solution by checking the equation is a good practice to ensure you've arrived at the correct answer. When solving \( -6(q+22)=5q \) and finding that \( q = -12 \), it's important to plug \( -12 \) back into the original equation. This means you replace \( q \) with \( -12 \) and perform the calculations:
\( -6(-12+22) = 5(-12) \)
which simplifies to \( -6(10) = -60 \), and \( 5(-12) = -60 \), confirming both sides equal \( -60 \) (not \( -120 \) as originally described in the solution).
This proof reinforces your confidence in the validity of the solution. Always remember to check your answers to avoid simple errors.
\( -6(-12+22) = 5(-12) \)
which simplifies to \( -6(10) = -60 \), and \( 5(-12) = -60 \), confirming both sides equal \( -60 \) (not \( -120 \) as originally described in the solution).
This proof reinforces your confidence in the validity of the solution. Always remember to check your answers to avoid simple errors.
Isolating Variables
The goal of solving linear equations is to find the value of an unknown variable. Once you've combined like terms and simplified the equation, you isolate the variable, which entails getting the variable on one side of the equation, and all numbers on the other. From our combined like terms \( -132 = 11q \), we isolate \( q \) by dividing both sides by \( 11 \) resulting in \( q = -12 \).
\( q = \frac{-132}{11} \) is the isolated variable, providing us the solution to the equation. Isolating the variable is a fundamental aspect of solving equations and mastering this technique is essential for algebraic success.
\( q = \frac{-132}{11} \) is the isolated variable, providing us the solution to the equation. Isolating the variable is a fundamental aspect of solving equations and mastering this technique is essential for algebraic success.
Other exercises in this chapter
Problem 85
Solve the equation. Check the result. (Review 3.4 ) $$y-9=2$$
View solution Problem 85
Graph the function. $$ h(x)=\frac{6}{5} x+5 $$
View solution Problem 86
In a school of 500 teens, 40 have taken drum lessons. What are the odds that a randomly chosen teen has not taken drum lessons?
View solution Problem 87
Solve the equation. Check the result. (Review 3.4 ) $$2(x+5)=18$$
View solution