Problem 86
Question
Solve each equation. \(x+\frac{3}{16}=-\frac{1}{2}\)
Step-by-Step Solution
Verified Answer
x = -\frac{11}{16}
1Step 1: Isolate the variable
To solve for \(x\), we need to move \(\frac{3}{16}\) to the right side of the equation. We do this by subtracting \(\frac{3}{16}\) from both sides. The equation becomes: \(x = -\frac{1}{2} - \frac{3}{16}\).
2Step 2: Find a common denominator
Before we can subtract \(-\frac{1}{2}\) and \(\frac{3}{16}\), we need to have a common denominator. Since 16 is a multiple of 2, we convert \(-\frac{1}{2}\) to \(-\frac{8}{16}\).
3Step 3: Perform the subtraction
Now that both fractions have the same denominator, we subtract: \(-\frac{8}{16} - \frac{3}{16} = -\frac{11}{16}\).
4Step 4: Write the final solution
The final answer for \(x\) is \(x = -\frac{11}{16}\).
Key Concepts
FractionsCommon DenominatorVariable Isolation
Fractions
Fractions represent a part of a whole and are written as one number over another, separated by a line, such as \(\frac{3}{16}\). The top number is called the numerator, and it tells us how many parts we have. The bottom number is the denominator, showing how many parts make up a whole.
Understanding fractions is crucial when solving equations because we often need to perform operations with them, such as adding or subtracting.
Understanding fractions is crucial when solving equations because we often need to perform operations with them, such as adding or subtracting.
- When fractions have the same denominator, you can easily add or subtract the numerators while keeping the denominator unchanged.
- If fractions have different denominators, you'll need a common denominator before you can add or subtract them.
Common Denominator
A common denominator is a shared multiple of the denominators of two or more fractions, allowing you to add or subtract them. The denominator acts as a 'common ground,' making calculations easier. In other words, when fractions share a common denominator, their numerators can be directly compared or calculated.
To find a common denominator, you typically look for the least common multiple (LCM) of the denominators. In the exercise, the fractions \(-\frac{1}{2}\) and \(\frac{3}{16}\) required a common denominator for subtraction.
To find a common denominator, you typically look for the least common multiple (LCM) of the denominators. In the exercise, the fractions \(-\frac{1}{2}\) and \(\frac{3}{16}\) required a common denominator for subtraction.
- If you have fractions like \(-\frac{1}{2}\) and \(\frac{3}{16}\), you can choose the smallest number both denominators divide into without remainder, like 16 in this case.
- Convert both fractions to have this new common denominator, transforming \(-\frac{1}{2}\) into \(-\frac{8}{16}\).
Variable Isolation
Variable isolation is the process of getting the variable alone on one side of the equation to find its value. This means you have a statement like \(x = ...\) that tells you exactly what the variable equals. It's an important step in solving any equation.
In our exercise, the variable \(x\) initially appears with other terms. To isolate \(x\), we need to move all other terms to the opposite side of the equation.
In our exercise, the variable \(x\) initially appears with other terms. To isolate \(x\), we need to move all other terms to the opposite side of the equation.
- This often involves using inverse operations, such as addition versus subtraction or multiplication versus division.
- In the given exercise, we subtracted \(\frac{3}{16}\) from both sides to shift it away from \(x\), leading to \(x = -\frac{1}{2} - \frac{3}{16}\).
Other exercises in this chapter
Problem 84
Solve each equation. \(x+\frac{5}{8}=-\frac{5}{6}\)
View solution Problem 85
Solve each equation. \(x-\frac{3}{5}=\frac{2}{3}\)
View solution Problem 87
Solve each equation. \(x-\frac{1}{6}=-\frac{7}{9}\)
View solution Problem 88
Solve each equation. \(x-\frac{3}{8}=-\frac{5}{24}\)
View solution