Problem 86
Question
Solve each equation in Exercises \(83-108\) by the method of your choice. $$5 x^{2}=6-13 x$$
Step-by-Step Solution
Verified Answer
The solution to the equation \(5x^{2}=6-13x\) is \( x=2 \) and \( x=0.6 \).
1Step 1: Identify a, b and c in the equation
The quadratic equation is in the format \( ax^{2} + bx + c = 0 \). Here \( a=5 \), \( b=-13 \) and \( c=6 \)
2Step 2: Apply the Quadratic Formula
The values should be placed into the quadratic formula: \( x=\frac{-(-13)\pm \sqrt{(-13)^{2} - 4 *5 *6}}{2 *(5)} \)
3Step 3: Simplify the expression
On simplifying the expression, you obtain \( x=\frac{13\pm \sqrt{169-120}}{10} \rightarrow x=\frac{13\pm \sqrt{49}}{10} \rightarrow x=\frac{13\pm 7}{10} \)
4Step 4: Calculate the solutions/roots
This gives you two roots: \( x=\frac{13+7}{10} = 2 \) and \( x=\frac{13-7}{10} = 0.6 \)
Key Concepts
Quadratic FormulaRoots of a Quadratic EquationSolving Quadratic Equations
Quadratic Formula
The quadratic formula is a powerful tool for solving quadratic equations, which are any polynomial equations of the form \( ax^2 + bx + c = 0 \). This formula provides a straightforward way to find the solutions, or "roots", for these types of equations. The quadratic formula is:
These solutions have different values depending on whether you add or subtract the square root term. Knowing the quadratic formula is essential for solving equations where rearranging or factoring isn't possible. It's important to substitute the correct values carefully to ensure accurate results.
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
These solutions have different values depending on whether you add or subtract the square root term. Knowing the quadratic formula is essential for solving equations where rearranging or factoring isn't possible. It's important to substitute the correct values carefully to ensure accurate results.
Roots of a Quadratic Equation
The roots of a quadratic equation are the values of \( x \) that satisfy the equation \( ax^2 + bx + c = 0 \). Mathematically, these roots are where the graph of the quadratic function, typically a parabola, intersects the x-axis.
- If the discriminant \( b^2 - 4ac > 0 \), there are two distinct real roots.
- If the discriminant \( b^2 - 4ac = 0 \), there is exactly one real root, also known as a repeated root.
- If the discriminant \( b^2 - 4ac < 0 \), there are no real roots; instead, the roots are complex numbers.
Solving Quadratic Equations
Solving quadratic equations can be done using various methods, including factoring, completing the square, and using the quadratic formula. The choice of method often depends on the specific form and coefficients of the equation.
- **Factoring**: Simplifies the equation by expressing it as a product of linear factors. This method works best when the equation can be easily decomposed into integers.
- **Completing the Square**: Transforms the equation into a perfect square trinomial, facilitating easier solving by taking square roots.
- **Using the Quadratic Formula**: Applies to any quadratic equation and is particularly useful when factoring is not straightforward.
Other exercises in this chapter
Problem 86
Solve absolute value inequality. \(9 \leq|4 x+7|\)
View solution Problem 86
Evaluate \(x^{2}-x\) for the value of \(x\) satisfying \(2(x-6)=3 x+2(2 x-1)\)
View solution Problem 87
Solve absolute value inequality. \(5>|4-x|\)
View solution Problem 87
Evaluate \(x^{2}-(x y-y)\) for \(x\) satisfying \(\frac{3(x+3)}{5}=2 x+6\) and \(y\) satisfying \(-2 y-10=5 y+18\)
View solution