Problem 86
Question
Show that for objects very far away (assume infinity), the magnification of any camera lens is proportional to its focal length.
Step-by-Step Solution
Verified Answer
The magnification is proportional to the focal length for distant objects.
1Step 1: Understanding Magnification Formula
Magnification (\( M \)) in terms of the camera lens is given by the ratio of the image distance (\( v \)) to the object distance (\( u \)): \[ M = \frac{v}{u} \].
2Step 2: Define Object at Infinity
For objects at infinity, the object distance \( u \) approaches infinity, hence the reciprocal \( \frac{1}{u} \) approaches zero for practical purposes.
3Step 3: Lens Formula Application
Use the lens formula: \( \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \). For an object at infinity, \( \frac{1}{u} = 0 \), simplifying the lens formula to \( \frac{1}{f} = \frac{1}{v} \). Therefore, \( v = f \).
4Step 4: Substitute in Magnification Formula
Substituting \( v = f \) into the magnification formula \( M = \frac{v}{u} \), we get \( M = \frac{f}{u} \). As \( u \rightarrow \infty \), the apparent size at the image plane viewed through the lens is dependent on \( f \), showing proportionality of magnification to the focal length.
Key Concepts
Focal LengthLens FormulaObject at Infinity
Focal Length
When we talk about camera lenses, a crucial concept is the focal length. The focal length of a lens is the distance from the lens to the point where it focuses light rays into a sharp image. This point is known as the focal point.
Think of the focal length as the lens's way of harnessing light and focusing it on something important. It determines how "zoomed in" one can get with an image and influences the field of view. A shorter focal length means a wider view, while a longer focal length offers a narrower but more in-depth view.
Think of the focal length as the lens's way of harnessing light and focusing it on something important. It determines how "zoomed in" one can get with an image and influences the field of view. A shorter focal length means a wider view, while a longer focal length offers a narrower but more in-depth view.
- A "normal" focal length for everyday photography is roughly equivalent to the diagonal length of your camera’s image sensor.
- Wide-angle lenses have short focal lengths and capture more of the scene in front of you.
- Telephoto lenses have longer focal lengths and are used for distant subjects, like sports or wildlife photography.
Lens Formula
The lens formula is a mathematical relationship that helps us understand how images are formed by lenses. It connects the focal length (\( f \)), image distance (\( v \)), and object distance (\( u \)) together in a simple equation:
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \]
This formula is vital for photographers and physicists alike, as it determines where the image will appear based on where an object is located relative to the lens.
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \]
This formula is vital for photographers and physicists alike, as it determines where the image will appear based on where an object is located relative to the lens.
- The term \( \frac{1}{f} \) represents the lens's ability to converge or diverge light.
- \( \frac{1}{v} \) is concerned with the image distance, the space from the lens to the image on the sensor.
- \( \frac{1}{u} \) deals with the distance from the lens to the object.
Object at Infinity
An essential scenario in lens optics is considering an object "at infinity." Let's break down what this means in practical terms. When we say an object is at infinity, it's really far away from the lens, such that its distance is vastly larger than any other distances in our setup.
In this case, the object distance \( u \) approaches infinity, making the reciprocal \( \frac{1}{u} \) nearly zero.
Due to this setup, the lens formula simplifies dramatically because the object is so distant:
\[ \frac{1}{f} = \frac{1}{v} \]
Here, the image distance \( v \) equals the focal length \( f \), which simplifies calculations. This insight is often used in astronomy and situations involving capturing distant landscapes.
In this case, the object distance \( u \) approaches infinity, making the reciprocal \( \frac{1}{u} \) nearly zero.
Due to this setup, the lens formula simplifies dramatically because the object is so distant:
\[ \frac{1}{f} = \frac{1}{v} \]
Here, the image distance \( v \) equals the focal length \( f \), which simplifies calculations. This insight is often used in astronomy and situations involving capturing distant landscapes.
- For photography, it suggests that distant subjects will converge to an image formed directly at the focal point.
- Practically, it means the lens is working at its optimal focal length.
- It also highlights the lens's efficiency in gathering light without distortion.
Other exercises in this chapter
Problem 84
If a 135-mm telephoto lens is designed to cover object distances from \(1.30 \mathrm{~m}\) to \(\infty\), over what distance must the lens move relative to the
View solution Problem 85
For a camera equipped with a 58 -mm-focal-length lens, what is the object distance if the image height equals the object height? How far is the object from the
View solution Problem 88
A converging lens with focal length of \(13.0 \mathrm{~cm}\) is placed in contact with a diverging lens with a focal length of \(-20.0 \mathrm{~cm} .\) What is
View solution Problem 89
An astronomical telescope has a magnification of \(8.0 \times .\) If the two lenses are \(28 \mathrm{~cm}\) apart, determine the focal length of each lens.
View solution