Problem 86
Question
I used the permutations formula to determine the number of ways people can select their 9 favorite baseball players from a team of 25 players.
Step-by-Step Solution
Verified Answer
The number of ways 9 players can be chosen from a team of 25 players can be calculated using the combination formula and the values for 'n' and 'r'.
1Step 1: Identify 'n' and 'r'
In the given problem, n represents the total number of baseball players, which is 25, and r represents the number of players to be chosen, which is 9.
2Step 2: Calculate Factorials
Calculate the factorials involved in the combination formula. So, calculate \(25!\), \(9!\) and \((25-9)!\).
3Step 3: Apply Combination Formula
Substitute the calculated values into the combination formula to calculate the total number of ways to select 9 players out of 25. Deducing, \[ C(25, 9) = \frac{25!}{9!(25-9)!} \]
4Step 4: Calculate Final Result
Perform the above calculations to find the final result.
Key Concepts
FactorialsCombination FormulaPermutations Formula
Factorials
Factorials are a fundamental concept in math, especially when dealing with permutations and combinations. They are denoted by an exclamation mark, and the factorial of a number, say 5, is written as \(5!\). A factorial is the product of all whole numbers from the specified number down to 1. For example:
In combinations and permutations, factorials help us calculate the total arrangements or selections possible. The larger the number, the larger the factorial, increasing rapidly to very big numbers! This is why factorials are so crucial in working out these types of problems. Understanding factorials can ease the complexity involved when calculating with the formulas, as they are the building blocks of many calculations.
- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)
- \( 3! = 3 \times 2 \times 1 = 6 \)
- \( 0! = 1 \) by convention
In combinations and permutations, factorials help us calculate the total arrangements or selections possible. The larger the number, the larger the factorial, increasing rapidly to very big numbers! This is why factorials are so crucial in working out these types of problems. Understanding factorials can ease the complexity involved when calculating with the formulas, as they are the building blocks of many calculations.
Combination Formula
When you are choosing items from a group where the order doesn't matter, you use combinations. This is exactly what was done with the baseball players—choosing favorites from a team. The combination formula is used to find out how many ways you can choose 'r' items from a group of 'n' items:\[C(n, r) = \frac{n!}{r! (n - r)!}\]In our baseball example, 'n' is 25 (total players) and 'r' is 9 (chosen players). The formula helps us determine the total possible combinations of choosing 9 players from 25, without considering the order.
By substituting the values into the formula, it's straightforward to calculate and find the total number of possible combinations.
- \( 25! \) represents all permutations of all players.
- \( 9! \) corrects for all arrangements of the chosen players.
- \( (25-9)! \) accounts for all possibilities of the remainders not chosen.
By substituting the values into the formula, it's straightforward to calculate and find the total number of possible combinations.
Permutations Formula
Permutations are used when the order of arrangement matters. However, in the particular baseball problem discussed, permutations aren't necessary since selection order isn't important. But generally, permutations allow us to calculate the different arrangements possible for a set of items where order is crucial.The permutations formula is:\[P(n, r) = \frac{n!}{(n - r)!}\]Here:
- \( n! \) is the factorial of the total number of items.
- \( (n-r)! \) is the factorial of the difference between the total and chosen items, removing the extra arrangements of remaining items.
Other exercises in this chapter
Problem 86
Among all pairs of numbers whose sum is \(24,\) find a pair whose product is as large as possible. What is the maximum product? (Section 3.1, Example 6)
View solution Problem 86
Solve: $$ 6|1-2 x|-7=11 $$
View solution Problem 87
$$ \text { Solve: } \quad \log _{2}(x+9)-\log _{2} x=1 . \text { (Section } 4.4, \text { Example } 7 \text { ) } $$
View solution Problem 88
What is a geometric sequence? Give an example with your explanation.
View solution