Problem 86
Question
For the following exercises, graph \(y=\sqrt[3]{x}\) on the given viewing window. Determine the corresponding range for each viewing window. Show each graph. $$ [-1,000,1,000] $$
Step-by-Step Solution
Verified Answer
The range for the viewing window is all real numbers.
1Step 1: Understand the function
The function given is \( y = \sqrt[3]{x} \), which represents the cube root of \( x \). The cube root function is defined for all real numbers and can have both positive and negative values.
2Step 2: Determine the domain
For the viewing window \([-1,000, 1,000]\), the domain is from \(-1,000\) to \(1,000\). This means we'll evaluate the cube root function for all these \(x\)-values.
3Step 3: Determine the range
The cube root function, \( y = \sqrt[3]{x} \), is always defined for all real numbers \(x\) and outputs all real numbers. Therefore, the range of this function over any domain is all real numbers. However, in practical graphing on a calculator, the visual range would be constrained by the graphing window's height limits.
4Step 4: Graph the function
To graph \( y = \sqrt[3]{x} \) from \(x = -1,000\) to \(x = 1,000\), plot a smooth curve passing through the origin \((0, 0)\) extending both to the left and to the right. The graph would look like an elongated S-shape, mirroring over the x-axis and y-axis. It increases slowly for negative \(x\)-values and steadily for positive \(x\)-values.
Key Concepts
Domain of the Cube Root FunctionRange of the Cube Root FunctionGraphing the Cube Root Function
Domain of the Cube Root Function
The domain of a function refers to all the possible input values (usually denoted as \(x\)) that can be used in the function to yield a valid output. In the case of the cube root function \(y = \sqrt[3]{x}\), the domain is all real numbers. This is because you can take the cube root of any real number, whether it's positive, negative, or zero. For our specific exercise, we are looking at the domain defined by the interval \([-1,000, 1,000]\). This means we'll consider every real number between \(-1,000\) and \(1,000\), inclusive. As you can imagine, that's quite a broad range! The cube root function will smoothly and continuously process each of these \(x\) values without restriction, emphasizing the comprehensiveness of its domain.In summary:
- The domain for \(y = \sqrt[3]{x}\) is all real numbers: \((-\infty, \infty)\).
- For our specific graph window, the domain is \([-1,000, 1,000]\).
- No values are excluded from the domain in any range selected for this function.
Range of the Cube Root Function
The range of a function represents all the potential outputs that can result when all the possible values of the domain are input into the function. For the cube root function \(y = \sqrt[3]{x}\), the range is similarly all real numbers. This means for any real number \(x\) you pick from the function's domain, \(y\) can be any real number.What's fascinating about \(y = \sqrt[3]{x}\) is that it isn't limited to non-negative values, unlike the square root function which only outputs zero or positive numbers. To illustrate, here are a few outcomes:
- \(x = 0\) results in \(y = 0\)
- A positive \(x\) like 8 will result in a positive \(y\) such as \(2\)
- A negative \(x\) like \(-8\) will correspondingly give a negative \(y\) like \(-2\)
Graphing the Cube Root Function
Graphing functions like \(y = \sqrt[3]{x}\) helps visualize how inputs relate to outputs and appreciate their behavior. The cube root function's graph has a distinctive elongated S-shape and is quite symmetrical.Steps for graphing:
- Start at the origin \(0, 0\), as \(\sqrt[3]{0} = 0\).
- For \(x\)-values that are positive, such as 1, 8, or 27, their cube roots (1, 2, and 3 respectively) are calculated smoothly and plotted above the \(x\)-axis.
- For negative \(x\)-values, like -1, -8, or -27, the corresponding \(y\) values (-1, -2, and -3) show the graph dipping below the \(x\)-axis.
- The curve moves leftwards and rightwards symmetrically from the origin, illustrating that the same magnitude of positive and negative inputs produces outputs of equal magnitude but opposite signs.
Other exercises in this chapter
Problem 86
Let \(F(x)=(x+1)^{5}, f(x)=x^{5},\) and \(g(x)=x+1\). True or False: \((f \circ g)(x)=F(x)\).
View solution Problem 86
For the following exercises, let \(F(x)=(x+1)^{5}, f(x)=x^{5},\) and \(g(x)=x+1\). True or False: \((f \circ g)(x)=F(x)\).
View solution Problem 87
Find the composition when \(f(x)=x^{2}+2\) for all \(x \geq 0\) and \(g(x)=\sqrt{x-2}\). $$ (f \circ g)(6) ;(g \circ f)(6) $$
View solution Problem 87
For the following exercises, find the composition when \(f(x)=x^{2}+2\) for all \(x \geq 0\) and \(g(x)=\sqrt{x-2}\). $$(f \circ g)(6) ;(g \circ f)(6)$$
View solution