Problem 86
Question
Find the standard form of the equation of the parabola with the given characteristics. Vertex: (-1,2)\(;\) focus: (-1,0)
Step-by-Step Solution
Verified Answer
The standard form equation of the parabola is \(y=-2(x+1)^2+2\).
1Step 1: Identify the Orientation and Vertex of the Parabola
From the given problem, we see that the parabola has a vertex at (-1,2) and a focus at (-1,0). Since only the y-coordinate changes, this tells us that the parabola opens either up or down. This is an important hint that to confirm the orientation.
2Step 2: Determine the Direction of the Parabola
A parabola always opens towards its focus. Here our focus is below the vertex, so the parabola opens downwards.
3Step 3: Find the Value of p
The value of p is the distance from the vertex to the focus, which in this instance is 2 units (2 - 0). But since the parabola opens downward, we use -2.
4Step 4: Write the Equation
Now, by plugging the values h = -1, k = 2 and p = -2 to the standard form equation \(y=k(x-h)²+k\) for a vertically oriented parabola, we arrive at the equation: \(y=-2(x+1)^2+2\).
Other exercises in this chapter
Problem 85
Find the standard form of the equation of the parabola with the given characteristics. Vertex: (5,2)\(;\) focus: (3,2)
View solution Problem 86
Describe the graph of the polar equation and find the corresponding rectangular equation. Sketch its graph. $$r=2 \csc \theta$$
View solution Problem 87
The center of a Ferris wheel lies at the pole of the polar coordinate system, where the distances are in feet. Passengers enter a car at \((30,-\pi / 2) .\) It
View solution Problem 87
Find the standard form of the equation of the parabola with the given characteristics. Vertex: (0,4)\(;\) directrix: \(y=2\)
View solution