Problem 86
Question
Find each product. Assume that the variables in the exponents represent positive integers. For example, $$ \left(x^{2 n}\right)\left(x^{3 n}\right)=x^{2 n+3 n}=x^{5 n} $$ $$\left(-5 x^{n-1}\right)\left(-6 x^{2 n+4}\right)$$
Step-by-Step Solution
Verified Answer
The product is \(30x^{3n+3}\).
1Step 1: Multiply the Constants
First, look at the constant terms in each part of the expression: \((-5) ext{ and } (-6)\)Multiplying these constants gives:\((-5) imes (-6) = 30\).
2Step 2: Apply Exponent Rules to the Variables
Next, consider the variable terms, specifically the powers of \(x\). We have:\(x^{n-1} ext{ and } x^{2n+4}\)Since we are multiplying powers of the same base, we can add the exponents:\(x^{(n-1) + (2n+4)}=x^{3n+3}\).
3Step 3: Combine Results
Combine the results from Step 1 and Step 2. The product is:\(30x^{3n+3}\).
Key Concepts
Multiplying ExponentsConstants MultiplicationAlgebraic Expressions
Multiplying Exponents
When multiplying exponents, it is important to identify exponents with the same base. In this context, a base is the number or variable that is being raised to a power. When we multiply these powers, we utilize the rule that states:
\[ a^m \times a^n = a^{m+n} \]This means we add the exponents while keeping the base constant.
\[ a^m \times a^n = a^{m+n} \]This means we add the exponents while keeping the base constant.
- For example, if you have \(x^{m}\times x^{n}\), the result will be \(x^{m+n}\).
- This simplifies complex expressions and reduces what might look like an intimidating equation into something more manageable.
Constants Multiplication
Multiplying constants simply involves the multiplication of numbers without any variables. This process translates to the basic arithmetic we are all familiar with.
- Start with the constants from each term of the expression. For instance, in the problem above, the constants \(-5\) and \(-6\) are multiplied together.
- Negative signs are important, as they affect the sign of the product. Multiplying two negative numbers results in a positive product: \((-5) \times (-6) = 30\).
Algebraic Expressions
Algebraic expressions make up the heart of algebra and are combinations of variables, numbers, and operators. Understanding how to manipulate them is a key part of solving algebraic problems.
- In any algebraic expression, terms are the individual components separated by + or - signs.
- Each term can include numbers (constants), variables (usually represented by letters), and exponents, reflecting the power to which the variable is raised.
Other exercises in this chapter
Problem 86
Should help you pull together all of the factoring techniques of this chapter. Factor completely each polynomial, and indicate any that are not factorable using
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Solve each equation for the indicated variable. \(x^{2}+a x+b x+a b=0\) for \(x\)
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Should help you pull together all of the factoring techniques of this chapter. Factor completely each polynomial, and indicate any that are not factorable using
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Set up an equation and solve each of the following problems. The square of a number equals seven times the number. Find the number.
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