Problem 86
Question
Factor the polynomial. $$ 2 a y^{2}-a x y+6 x y-3 x^{2} $$
Step-by-Step Solution
Verified Answer
The polynomial factors to \((2y - x)(ay + 3x)\).
1Step 1: Group Terms That Can Be Factored Together
First, group the terms in such a way that the first two terms can be factored together, and the last two terms can be factored together: \[ 2ay^2 - axy + 6xy - 3x^2 \] becomes \[ (2ay^2 - axy) + (6xy - 3x^2) \].
2Step 2: Factor Out the Greatest Common Factor (GCF) of Each Group
For the first group \((2ay^2 - axy)\), the GCF is \(ay\). Thus, you can factor it as: \[ ay(2y - x) \].For the second group \((6xy - 3x^2)\), the GCF is \(3x\). Thus, it can be factored as: \[ 3x(2y - x) \].
3Step 3: Identify and Factor the Common Binomial Factor
Notice that \((2y - x)\) is a common binomial factor in the expressions that result from the factored groups:\[ ay(2y - x) + 3x(2y - x) \]. Factor out the common binomial factor \((2y - x)\):\[ (2y - x)(ay + 3x) \].
4Step 4: Final Step: Verify the Factored Form
Distribute to check if the factored result is correct:\[((2y - x)(ay + 3x)) = 2ay^2 + 6xy - axy - 3x^2 \]. This simplifies back to the original polynomial, confirming the factorization is correct.
Key Concepts
Greatest Common Factor (GCF)Binomial FactorDistributive Property
Greatest Common Factor (GCF)
The Greatest Common Factor, or GCF, is a crucial concept in polynomial factorization. It refers to the largest factor that divides two or more numbers or terms without leaving a remainder. For polynomials, finding the GCF is essential as it simplifies expressions and aids in the factorization process. In the exercise, two groups of terms were identified:
- The first group: \(2ay^2 - axy\)
- The second group: \(6xy - 3x^2\)
Binomial Factor
Binomial factors are expressions that consist of two terms, like \( (a + b) \). In polynomial factorization, finding a common binomial factor can be a hidden gem that simplifies expressions significantly. Once each group from the polynomial is factored using their GCF, the expression takes the form: \[ ay(2y - x) + 3x(2y - x) \]In this expression, \(2y - x\) emerges as a common binomial factor in both terms. Recognizing this common factor is key, making the factorization process efficient. By factoring out this repeated binomial, the polynomial simplifies to:\[(2y - x)(ay + 3x)\]This step helps unravel seemingly complex polynomials and transform them into simpler factors that are much more manageable.
Distributive Property
The distributive property is a fundamental algebraic property that is essential in polynomial factorization. It allows you to multiply a sum by multiplying each term inside the parentheses by a factor outside them. Here's how it works: If you have an expression such as \( (a + b)c \), the distributive property gives us: \[ ac + bc \]In factorization, distributive property is applied backward. For instance, when we find our common binomial factor \( (2y - x)(ay + 3x) \), we ensure the expression is correctly factored by distributing:\[(2y - x)(ay) + (2y - x)(3x)\]Using the distributive property verifies that our factored expression multiplies back to the initial polynomial, confirming the correctness of the factorization: \[ 2ay^2 + 6xy - axy - 3x^2 \]Understanding this property is essential to grasp how factorization goes hand in hand with multiplication, maintaining the equality between expressions.
Other exercises in this chapter
Problem 85
Factor the polynomial. $$ 2 a x-6 b x+a y-3 b y $$
View solution Problem 85
Exer. 85-90: Replace the symbol \(\square\) with either \(=\) or \(\neq\) to make the resulting statement true, whenever the expression has meaning. Give a reas
View solution Problem 86
Exer. 85-90: Replace the symbol \(\square\) with either \(=\) or \(\neq\) to make the resulting statement true, whenever the expression has meaning. Give a reas
View solution Problem 87
Factor the polynomial. $$ 3 x^{3}+3 x^{2}-27 x-27 $$
View solution