Problem 86
Question
Factor the expression. \(25 y^{3}-20 y^{2}+4 y\)
Step-by-Step Solution
Verified Answer
The expression factors to \(y(5y - 2)^2\).
1Step 1: Identify the Greatest Common Factor (GCF)
First, look for the greatest common factor (GCF) among all the terms in the expression. The terms are: \(25y^3\), \(-20y^2\), and \(4y\). The GCF here is \(y\) because each term contains at least one \(y\).
2Step 2: Factor out the GCF
Factor \(y\) out of the entire expression. Therefore: \(25y^3 - 20y^2 + 4y = y(25y^2 - 20y + 4)\).
3Step 3: Rewrite the Quadratic Expression
Now, focus on factoring the quadratic expression inside the parenthesis: \(25y^2 - 20y + 4\). Remember, this is in the form of \(ax^2 + bx + c\), where \(a = 25\), \(b = -20\), and \(c = 4\).
4Step 4: Factor the Trinomial by Grouping
To factor \(25y^2 - 20y + 4\), we need factors of \(25 \times 4 = 100\) that add to \(-20\). These are \(-10\) and \(-10\). Rewrite the middle term: \(25y^2 - 10y - 10y + 4\).
5Step 5: Group Terms and Factor
Group terms in pairs: \((25y^2 - 10y) + (-10y + 4)\). Factor each pair: \(5y(5y - 2) - 2(5y - 2)\). Notice \(5y - 2\) is common in both groups.
6Step 6: Factor Out the Common Binomial
Factor out the common binomial \((5y - 2)\): \((5y - 2)(5y - 2)\). Thus, \(25y^2 - 20y + 4 = (5y - 2)^2\).
7Step 7: Combine with the GCF
Bring back the factored GCF from Step 2: \(y(5y - 2)^2\). So, the expression \(25y^3 - 20y^2 + 4y\) is fully factored as \(y(5y - 2)^2\).
Key Concepts
Greatest Common FactorTrinomial FactoringBinomial FactoringAlgebraic Expressions
Greatest Common Factor
When you approach factoring polynomials, finding the greatest common factor (GCF) is often the first step. The GCF is the highest factor that evenly divides all terms in a given expression. Take the expression from the original exercise:
- The terms are: \(25y^3\), \(-20y^2\), and \(4y\).
- The highest common factor among these terms is \(y\), as each term contains at least one \(y\).
Trinomial Factoring
After isolating any common factors, your next target is often factoring a trinomial. Trinomials are polynomials with three terms, generally given in the form \(ax^2 + bx + c\). For our example, the expression inside the brackets, \(25y^2 - 20y + 4\), is a trinomial.
- The goal is to break this expression down into simpler binomial factors.
- We look for two numbers that multiply to \(a \times c\) (in this case, \(25 \times 4 = 100\)), and add to \(b\) (\(-20\)). Here, the numbers are \(-10\) and \(-10\).
Binomial Factoring
Factoring binomials involves expressing a polynomial as a product of two binomial expressions. After writing the middle term of the trinomial in terms of two numbers, you can proceed with binomial factoring.In our exercise, we wrote:\[ 25y^2 - 10y - 10y + 4 \]Next, group and factor these terms:
- Group: \((25y^2 - 10y) + (-10y + 4)\).
- Factor each pair: \(5y(5y - 2) - 2(5y - 2)\).
Algebraic Expressions
Algebraic expressions are mathematical phrases involving numbers and variables that use operational symbols. When working with algebraic expressions, especially polynomials, factoring simplifies complex expressions into manageable parts.In the expression \(25y^3 - 20y^2 + 4y\):
- The terms are manipulated through various factoring methods to express them in simpler forms.
- Factoring techniques, such as identifying the GCF or trinomial factoring, make operations like solving equations, simplifying fractions, and evaluating expressions much easier.
Other exercises in this chapter
Problem 86
Exercises \(65-90:\) Use rules of exponents to simplify the expression. Use positive exponents to write your answer. $$ \frac{(2 r t)^{2}}{\left(r t^{4}\right)^
View solution Problem 86
Simplify the expression. Assume that all variables are positive. $$ \sqrt[4]{x y^{3}}+\sqrt[4]{x^{5} y} $$
View solution Problem 86
Simplify the expression and write it with rational exponents. Assume that all variables are positive. $$ \left(\frac{x^{6}}{81}\right)^{1 / 4} $$
View solution Problem 86
Simplify. $$ \frac{a^{2}+1}{a^{2}-1}+\frac{a}{1-a^{2}} $$
View solution