Problem 86
Question
Factor by grouping. $$x^{2}+a x+b x+a b$$
Step-by-Step Solution
Verified Answer
The factored form of the expression \(x^{2}+a x+b x+a b\) by grouping is \((x + a)(x + b)\).
1Step 1: Identify the Groups
Firstly, we identify the groups. The given expression can be expressed as groups in the following manner:\(x^{2}+a x\) and \(+b x+a b\) are the two groups.
2Step 2: Factor Out the Common Factors
Now, factor out the common factor from each group. From the first group \(x^{2}+a x\) we can take out \(x\), which leaves us with \(x(x+a)\). From the second group \(b x+a b\), we can factor out \(b\), giving \(b(x + a)\).
3Step 3: Factor Out the Common Binomial
Now, factor out the common binomial. The expression can be rewritten as:\(x(x + a) + b(x + a)\). Here, the common binomial is \((x + a)\). Factoring that out gives us:\((x + a)(x + b)\). This is the factored form of the original expression.
Key Concepts
Algebraic ExpressionsFactoring TechniquesIntroductory Algebra
Algebraic Expressions
Understanding algebraic expressions is crucial when learning algebra. An algebraic expression is a mathematical phrase that can contain numbers, variables, and arithmetic operations such as addition, subtraction, multiplication, and division.
These expressions often represent real-world problems or situations that can be modeled mathematically by using symbols.
These expressions often represent real-world problems or situations that can be modeled mathematically by using symbols.
- Variables: Symbols, often letters, that represent unknown values. In our example, the variables used are \(x\) and \(a\).
- Terms: Parts of the expression separated by plus or minus signs. In the expression \(x^{2}+ax+bx+ab\), each separate part is a term.
- Coefficients: Numbers that multiply the variable in any given term. For instance, in \(ax\), \(a\) is the coefficient.
Factoring Techniques
Factoring is a method of breaking down an algebraic expression into simpler components that, when multiplied together, give the original expression. There are several techniques for factoring, but here we focus on the method of "factoring by grouping."This technique is particularly useful when dealing with polynomials that have four terms. Let's break down the strategy:
- Identify groups: Divide the expression into two pairs. For example, the expression \(x^{2}+ax+bx+ab\) can be grouped as \(x^{2}+ax\) and \(bx+ab\).
- Factor each group separately: Look for common factors within each group. The first group \(x^{2}+ax\) has a common factor of \(x\) and the second group \(bx+ab\) has a common factor of \(b\).
- Combine the factored groups: Once you factor out the common factors, you can rearrange the expression. The goal is to find a common binomial factor in both terms, such as \((x+a)\), to simplify further.
Introductory Algebra
Learning introductory algebra involves grasping the basic principles and operations of algebra. At this stage, students should become comfortable with manipulating and solving simple algebraic expressions and equations.
Some key aspects of introductory algebra include:
- Simplification: Reducing expressions to their simplest form, often through factoring or combining like terms.
- Solving equations: Determining the value of unknown variables that make the equation true.
- Understanding properties: Familiarity with properties of mathematical operations, such as commutative and associative properties, helps in rearranging and simplifying equations more effectively.
Other exercises in this chapter
Problem 86
Give two helpful suggestions for factoring \(x^{2}-5 x+6\)
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Factor using the formula for the sum or difference of two cubes. $$125 x^{3}+8$$
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Factor completely. $$12 a^{2} b-34 a b^{2}+14 b^{3}$$
View solution Problem 87
Contain polynomials in several variables. Factor each polynomial completely and check using multiplication. $$72 a^{3} b^{2}+12 a^{2}-24 a^{4} b^{2}$$
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