Problem 86
Question
Explain why \(\mathrm{SO}_{2}\) can be used as a reducing agent but \(\mathrm{SO}_{3}\) cannot.
Step-by-Step Solution
Verified Answer
SO₂ can be used as a reducing agent because it can donate electrons and be oxidized to SO₃, where sulfur has its highest oxidation state of +6. In contrast, SO₃ cannot act as a reducing agent since sulfur is already in its highest oxidation state and cannot be further oxidized or donate electrons.
1Step 1: Understand Reducing Agents
A reducing agent is a substance that can reduce other substances, which means it can donate electrons to other substances during a chemical reaction. Reducing agents themselves are oxidized in the process, meaning they lose electrons. To determine if a molecule can act as a reducing agent, we should examine its ability to donate electrons and its willingness to be oxidized.
2Step 2: Examine Oxidation States and Stability of SO₂
In SO₂, the sulfur atom has an oxidation state of +4. SO₂ is able to be oxidized further to SO₃, in which sulfur has the oxidation state of +6, the highest possible oxidation state for sulfur. In this process, SO₂ donates electrons to other molecules, reducing them and becoming more oxidized itself:
SO₂ + ½ O₂ → SO₃
Thus, SO₂ can act as a reducing agent, as it can donate electrons and be oxidized.
3Step 3: Examine Oxidation States and Stability of SO₃
In SO₃, the sulfur atom has the oxidation state of +6. This is the highest possible oxidation state for sulfur, meaning SO₃ cannot be oxidized further. Since it cannot be further oxidized, SO₃ has no electrons to donate and cannot act as a reducing agent.
4Step 4: Compare SO₂ and SO₃
Comparing the oxidation states and stability of SO₂ and SO₃, it is clear that SO₂ can act as a reducing agent because it is capable of donating electrons while being oxidized to SO₃. In contrast, SO₃ is already in its highest oxidation state and cannot be further oxidized, making it unable to act as a reducing agent.
Overall: SO₂ can be used as a reducing agent due to its ability to donate electrons and be oxidized to SO₃, while SO₃ cannot be used as a reducing agent because it is already in its highest oxidation state and cannot be further oxidized.
Other exercises in this chapter
Problem 84
What is the anhydride for each of the following acids: (a) \(\mathrm{H}_{2} \mathrm{SO}_{4}\), (b) \(\mathrm{HClO}_{3}\), (c) \(\mathrm{HNO}_{2}\), (d) \(\mathr
View solution Problem 85
Hydrogen peroxide is capable of oxidizing (a) hydrazine to \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\), (b) \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{4}^{2
View solution Problem 88
(a) What is the oxidation state of \(\mathrm{P}\) in \(\mathrm{PO}_{4}{\underline{\phantom{xx}}}^{3-}\) and of \(\mathrm{N}^{-}\)in \(\mathrm{NO}_{3}{\underline{\phantom{xx}}}^{-}\)? (b) Why doesn't N form
View solution Problem 89
(a) The \(\mathrm{P}_{4}, \mathrm{P}_{4} \mathrm{O}_{6}\) and \(\mathrm{P}_{4} \mathrm{O}_{10}\) molecules have a common structural feature of four \(\mathrm{P}
View solution