Problem 86
Question
Explain when the \(\mathrm{LCD}\) is the same as one of the denominators of a rational expression to be added or subtracted.
Step-by-Step Solution
Verified Answer
The LCD matches a denominator if one is a multiple of all others.
1Step 1: Understanding LCD
The Lowest Common Denominator (LCD) is the smallest number that all denominators in a set of fractions can divide without leaving a remainder. To find the LCD, identify the least common multiple (LCM) of the denominators involved.
2Step 2: Identify Denominators
First, take note of the denominators involved in the rational expressions that need to be added or subtracted. For example, if the rational expressions are \( \frac{1}{4} \) and \( \frac{1}{6} \), the denominators are 4 and 6.
3Step 3: Find LCM of Denominators
Calculate the least common multiple of the denominators. For denominators 4 and 6, the multiples are 4 (4, 8, 12, 16, ...) and 6 (6, 12, 18, ...). The least common multiple is 12.
4Step 4: Condition for LCD Match
The LCD is the same as one of the denominators when that denominator is a multiple of all other denominators. In simpler terms, if one denominator can be equally divided into the other denominators without leaving a remainder, it is the LCD.
5Step 5: Apply to Example
In the example of denominators 4 and 12, since 12 is a multiple of 4, the LCD is 12, which matches one of the original denominators.
Key Concepts
Least Common Multiple (LCM)rational expressionsadding and subtracting fractions
Least Common Multiple (LCM)
The Least Common Multiple (LCM) is crucial when working with rational expressions, especially for finding the Lowest Common Denominator (LCD). The LCM is the smallest number that is a multiple of two or more numbers. For instance, if you're dealing with numbers like 4 and 6, you list down their multiples: for 4 (4, 8, 12, 16, ...), and for 6 (6, 12, 18, ...). The smallest common multiple is 12. Thus, 12 is the LCM of 4 and 6.
Using the LCM helps streamline operations involving fractions. It leads to efficiently finding the LCD of fractional denominators, allowing you to perform additions or subtractions with ease. In practice, if you notice that an LCM of denominators aligns with one of the denominators, it simplifies your calculations, making it easier to manipulate the fractions.
Using the LCM helps streamline operations involving fractions. It leads to efficiently finding the LCD of fractional denominators, allowing you to perform additions or subtractions with ease. In practice, if you notice that an LCM of denominators aligns with one of the denominators, it simplifies your calculations, making it easier to manipulate the fractions.
rational expressions
Rational expressions are fractions that involve polynomials in their numerators and denominators. They resemble numerical fractions, but they manipulate polynomial terms, like \( \frac{x+2}{x-1} \) or \( \frac{2x}{x^2-4} \). Since dealing with these expressions involves polynomial division, having a strong grasp of factoring plays a pivotal role.
When you need to add or subtract rational expressions, understanding the structure of these expressions is vital. Recognizing the components helps in identifying common denominators more readily. Simplifying before addition or subtraction is often necessary, where you might factorize the numerator or denominator to discover and cancel common factors across the expressions.
When you need to add or subtract rational expressions, understanding the structure of these expressions is vital. Recognizing the components helps in identifying common denominators more readily. Simplifying before addition or subtraction is often necessary, where you might factorize the numerator or denominator to discover and cancel common factors across the expressions.
adding and subtracting fractions
Adding and subtracting fractions, including rational expressions, requires a shared denominator. This is where the LCD comes in — it ensures the denominators are equal to facilitate straightforward operations. Start by identifying all denominators involved in your fractions. Then, find the LCM of these denominators to establish your LCD.
Once you determine the LCD, adjust your fractions accordingly, converting each fraction so their denominators match the LCD. This uniformity allows you to directly add or subtract the numerators while keeping the denominator unchanged.
For example, with rational expressions \( \frac{a}{b} \) and \( \frac{c}{d} \), you find the LCM of \( b \) and \( d \) to get your LCD. Adjust the fractions to \( \frac{a(d)}{b(d)} \) and \( \frac{c(b)}{d(b)} \) so both have the LCD as their denominator, thereafter, proceed with addition or subtraction. This systematic approach minimizes mistakes and aligns your process across different expressions.
Once you determine the LCD, adjust your fractions accordingly, converting each fraction so their denominators match the LCD. This uniformity allows you to directly add or subtract the numerators while keeping the denominator unchanged.
For example, with rational expressions \( \frac{a}{b} \) and \( \frac{c}{d} \), you find the LCM of \( b \) and \( d \) to get your LCD. Adjust the fractions to \( \frac{a(d)}{b(d)} \) and \( \frac{c(b)}{d(b)} \) so both have the LCD as their denominator, thereafter, proceed with addition or subtraction. This systematic approach minimizes mistakes and aligns your process across different expressions.
Other exercises in this chapter
Problem 86
A company's gross profit margin \(P\) can be computed with the formula \(P=\frac{R-C}{R},\) where \(R=\) the company's revenue and \(C=\) cost of goods sold. Fo
View solution Problem 86
The Penske Racing team has been involved in the Indianapolis 500 for many successful years. Two of its drivers, Helio Castroneves and Ryan Briscoe, placed 4th a
View solution Problem 87
A baseball player's slugging percentage \(S\) can be calculated with the following formula: \(S=\frac{h+d+2 t+3 r}{b},\) where \(h=\) number of hits, \(d=\) num
View solution Problem 88
To calculate a quarterback's rating in NCAA football, you may use the formula \(\frac{100 C+330 T-200 I+8.4 Y}{A}\), where \(C=\) the number of completed passes
View solution