Problem 86
Question
Double-acting baking powder contains two salts, sodium hydrogen carbonate and potassium dihydrogen phosphate, whose anions react in water to form \(\mathrm{CO}_{2}\) gas. Write a balanced chemical equation for the reaction. Which anion is the acid and which is the base?
Step-by-Step Solution
Verified Answer
The balanced equation is: \(\text{HCO}_3^- + \text{H}_2\text{PO}_4^- \rightarrow \text{H}_3\text{PO}_4 + \text{CO}_2 + \text{H}_2\text{O}\). \(\text{H}_2\text{PO}_4^-\) is the acid, and \(\text{HCO}_3^-\) is the base.
1Step 1: Identify the Anions Involved
Sodium hydrogen carbonate contains the anion bicarbonate \((\text{HCO}_3^-)\), while potassium dihydrogen phosphate contains the anion dihydrogen phosphate \((\text{H}_2\text{PO}_4^-)\). These are the reacting anions in the double-acting baking powder.
2Step 2: Determine the role of Anions
The bicarbonate ion (\(\text{HCO}_3^-\)) can act as a conjugate base in reactions, while the dihydrogen phosphate ion (\(\text{H}_2\text{PO}_4^-\)) can act as an acid.
3Step 3: Write the Reaction Equation
In water, bicarbonate (base) accepts a proton from dihydrogen phosphate (acid), releasing \( ext{CO}_2\) gas. The balanced chemical equation is: \[ \text{HCO}_3^- + \text{H}_2\text{PO}_4^- \rightarrow \text{H}_3\text{PO}_4 + \text{CO}_2 + \text{H}_2\text{O} \]
4Step 4: Classify Acid and Base
In the reaction, \(\text{H}_2\text{PO}_4^-\) donates a proton, making it the acid, while \(\text{HCO}_3^-\) accepts a proton, making it the base.
Key Concepts
Acid-Base ReactionsBalancing Chemical EquationsBicarbonate and Phosphate Reactions
Acid-Base Reactions
Acid-base reactions are a fascinating part of chemistry that involve a transfer of protons between reactants. These reactions can occur in various systems, including solutions and gases. Typically, an acid donates a proton ( ext{H}^+), whereas a base accepts this proton. For double-acting baking powder, a common household item, this concept plays a vital role in its function. Here, we see the bicarbonate ion ( ext{HCO}_3^-) acting as a base, accepting a proton from the dihydrogen phosphate ion ( ext{H}_2 ext{PO}_4^-) which is acting as an acid. This proton transfer causes the release of carbon dioxide ( ext{CO}_2) gas, which helps baked goods rise. Understanding these interactions helps in predicting the outcome of combining different substances. A key takeaway is always to remember that acids are proton donors and bases are proton acceptors.
Balancing Chemical Equations
Balancing chemical equations is a critical skill in chemistry that ensures mass conservation during a chemical reaction. Every atom on the reactants' side must be accounted for on the products' side. The reaction involving bicarbonate and dihydrogen phosphate in baking powder can be described by a balanced chemical equation.
- Start by writing the chemical formulas of the reactants and products.
- Ensure the number of each type of atom is the same on both sides of the equation.
- Adjust coefficients as needed to balance the atoms.
Bicarbonate and Phosphate Reactions
These reactions are particularly interesting as they involve bicarbonate ( ext{HCO}_3^-), a common compound known for its role in baking and pharmaceuticals, and phosphate ions, which are critical in biological systems. When these two anions react in water, an acid-base reaction occurs.
- Bicarbonate, acting as the base, accepts a proton from the dihydrogen phosphate, releasing carbon dioxide gas.
- The dihydrogen phosphate ( ext{H}_2 ext{PO}_4^-) acts as the acid and donates a proton.
Other exercises in this chapter
Problem 84
Write the formula for the conjugate acid of \(\left[\mathrm{Zn}(\mathrm{OH})_{4}\right]^{2-} .\)
View solution Problem 85
Write the formula for the conjugate base of \(\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3}(\mathrm{OH})\right]^{1+}\).
View solution Problem 87
Common soap is made by reacting sodium carbonate with stearic acid, \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{16} \mathrm{COOH}\). Write a balanced equatio
View solution Problem 89
Why is it not a good idea to substitute dishwashing detergent for automobile- washing detergent?
View solution