Problem 86
Question
A transparent rod 30.0 \(\mathrm{cm}\) long is cut flat at one end and rounded to a hemispherical surface of radius 10.0 \(\mathrm{cm}\) at the other end. A small object is embedded within the rod along its axis and halfway between its ends, 15.0 \(\mathrm{cm}\) from the flat end and 15.0 \(\mathrm{cm}\) from the vertex of the curved end. When viewed from the flat end of the rod, the apparent depth of the object is 9.50 \(\mathrm{cm}\) from the flat end. What is its apparent depth when viewed from the curved end?
Step-by-Step Solution
Verified Answer
The apparent depth from the curved end is 8.02 cm.
1Step 1: Understand the Apparent Depth Formula
The apparent depth for a flat surface can be calculated using the formula: \[D_{apparent} = \frac{D_{real}}{n}\]where \(D_{apparent}\) is the apparent depth, \(D_{real}\) is the real depth, and \(n\) is the refractive index of the rod material.
2Step 2: Calculate the Refractive Index
Given the apparent depth from the flat end is 9.50 cm, and the real depth from the flat end is 15.0 cm. Using the formula:\[9.50 = \frac{15.0}{n}\]Solving for \(n\), we multiply both sides by \(n\) and divide by 9.50 cm to get:\[n = \frac{15.0}{9.50} \approx 1.58\]
3Step 3: Use Lens Formula for the Curved Surface
For the curved end, we use the lens maker's formula for apparent depth:\[D_{apparent, curved} = \frac{R \cdot D_{real}}{(R - D_{real}) + n \cdot D_{real}}\]where \(R\) is the radius of curvature and \(D_{real}\) is the distance from the object to the vertex of the surface.
4Step 4: Substitute Known Values and Solve
Here, \(R = 10.0\) cm, \(D_{real} = 15.0\) cm, and \(n = 1.58\). Substitute these values into the equation:\[D_{apparent, curved} = \frac{10.0 \cdot 15.0}{(10.0 - 15.0) + 1.58 \cdot 15.0}\]Calculate the denominator:\[(10.0 - 15.0) + 1.58 \cdot 15.0 = -5.0 + 23.7 = 18.7\]So,\[D_{apparent, curved} = \frac{150.0}{18.7} \approx 8.02 \text{ cm}\]
5Step 5: Conclusion
The apparent depth of the object when viewed from the curved end of the rod is approximately 8.02 cm.
Key Concepts
Refractive IndexLens Maker's FormulaRadius of Curvature
Refractive Index
The refractive index is a fundamental property of materials that describes how light propagates through them. Simply put, it tells us how much slower light travels in the material compared to a vacuum. This is important when dealing with optical devices like lenses or transparent rods, as it affects how we perceive the position of objects behind these materials. Specifically, for any material, the refractive index can be calculated using the formula:
In our problem, we used the refractive index to find out how the depth of an object changes when viewed through a transparent rod. By comparing the real depth (how deep the object truly is) with the apparent depth (how deep it appears), we can use the formula:
- Refractive Index (\(n\)):\(n = \frac{c}{v}\)
In our problem, we used the refractive index to find out how the depth of an object changes when viewed through a transparent rod. By comparing the real depth (how deep the object truly is) with the apparent depth (how deep it appears), we can use the formula:
- \(D_{apparent} = \frac{D_{real}}{n}\)
Lens Maker's Formula
The lens maker's formula is a useful equation in optics, particularly when dealing with lenses that have curved surfaces. It allows us to calculate the apparent depth or position of an object seen through such lenses. This formula is slightly more complex than the one for a flat surface because it accounts for curvature. The lens maker’s formula for apparent depth through a curved surface is as follows:
- \(D_{apparent, curved} = \frac{R \cdot D_{real}}{(R - D_{real}) + n \cdot D_{real}}\)
- \(R\)is the radius of curvature of the lens,
- \(D_{real}\)is the real depth or distance from the object to the lens's vertex,
- and\(n\)is the refractive index.
Radius of Curvature
The radius of curvature is a critical concept in lens and optics. It describes the radius of the hypothetical sphere from which a curved surface or lens is a part. Understanding the radius of curvature helps us understand how strongly the lens will converge or diverge light.
In optics, the power of a lens and the way it manipulates light largely depend on this radius. A smaller radius of curvature implies a stronger bending of light, while a larger radius indicates a gentler curve.
In optics, the power of a lens and the way it manipulates light largely depend on this radius. A smaller radius of curvature implies a stronger bending of light, while a larger radius indicates a gentler curve.
- When applied to the problem, a radius of 10.0 cm was used to represent the curvature of the rod's hemispherical surface.
Other exercises in this chapter
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A transparent rod 50.0 \(\mathrm{cm}\) long and with a refractive index of 1.60 is cut flat at the right end and rounded to a hemispherical surface with a 15.0
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