Problem 85
Question
To determine age-specific mortality, a group of individuals, all born at the same time, is followed over time. If \(N(t)\) denotes the number still alive at time \(t\), then \(N(t) / N(0)\) is the fraction surviving at time \(t\). The quantity \(r(t)\), called the hazard rate function, measures the rate at which individuals die at time \(t\); that is, \(r(t) d t\) is the probability that an individual who is alive at time \(t\) dies during the infinitesimal time interval \((t, t+d t)\). The cumulative hazard during the time interval \([0, t], \int_{0}^{t} r(s) d s\), can be estimated as \(-\ln \frac{N(t)}{N(0)}\). Show that the cumulative hazard during the time interval \([t, t+1], \int_{t}^{t+1} r(s) d s\), can be estimated as \(-\ln \frac{N(t+1)}{N(t)}\).
Step-by-Step Solution
VerifiedKey Concepts
Hazard rate function
Here's how it works:
- \(r(t) \, dt\) is the probability that an individual who has survived up to time \(t\) will depart in the infinitesimally short interval \((t, t + dt)\).
- Think of \(r(t)\) as a speedometer for mortality risk; when \(r(t)\) is high, the risk is swift, and when it's low, life seems rather safe.
- The function gives crucial insights allowing us to predict how a population diminishes over time, without needing to track each individual's life span separately.
Cumulative hazard
Why is this useful?
- It offers a snapshot of the total hazard or risk accumulated over a period, summing up all the mini risks provided by \(r(s)\) at every slice of time \(s\).
- Estimating the cumulative hazard for a narrower window, \([t, t+1]\), is much like zooming in, calculated as \(-\ln \left( \frac{N(t+1)}{N(t)} \right)\).
- Understanding this function helps detect patterns or changes in risk, and gives power to predict future survival scenarios.
Survival probability
What does it signify?
- This fraction reveals just how many have weathered the journey to age \(t\), shielding insights into the effects of time, as well as age, health, and environmental factors.
- For future points, like \([t, t+1]\), it updates as \(\frac{N(t+1)}{N(t)}\), marking a fresh survival outlook post \(t\).
- By understanding survival probability's dance with time, we can tap into patterns or disruptions in population health.