Problem 85
Question
Specify which of the following are oxidation-reduction reactions, and identify the oxidizing agent, the reducing agent, the substance being oxidized, and the substance being reduced. a. \(\mathrm{Cu}(s)+2 \mathrm{Ag}^{+}(a q) \rightarrow 2 \mathrm{Ag}(s)+\mathrm{Cu}^{2+}(a q)\) b. \(\mathrm{HCl}(g)+\mathrm{NH}_{3}(g) \rightarrow \mathrm{NH}_{4} \mathrm{Cl}(s)\) c. \(\mathrm{SiCl}_{4}(l)+2 \mathrm{H}_{2} \mathrm{O}(l) \rightarrow 4 \mathrm{HCl}(a q)+\mathrm{SiO}_{2}(s)\) d. \(\mathrm{SiCl}_{4}(l)+2 \mathrm{Mg}(s) \rightarrow 2 \mathrm{MgCl}_{2}(s)+\mathrm{Si}(s)\) e. \(\mathrm{Al}(\mathrm{OH})_{4}^{-}(a q) \rightarrow \mathrm{AlO}_{2}^{-}(a q)+2 \mathrm{H}_{2} \mathrm{O}(i)\)
Step-by-Step Solution
Verified Answer
In conclusion, only reactions a and d are oxidation-reduction reactions.
For reaction a:
- Oxidizing agent: Ag¹⁺(aq)
- Reducing agent: Cu(s)
- Substance being oxidized: Cu(s)
- Substance being reduced: Ag¹⁺(aq)
For reaction d:
- Oxidizing agent: SiCl₄(l)
- Reducing agent: Mg(s)
- Substance being oxidized: Mg(s)
- Substance being reduced: SiCl₄(l)
1Step 1: Identify reaction type and changes in oxidation numbers
To see if the reaction is redox, we will calculate the oxidation numbers of elements before and after the reaction:
Cu: 0 -> +2
Ag: +1 -> 0
Cu has increased in oxidation number (lost electrons) and thus, undergoes oxidation, turning to Cu²⁺(aq). Ag¹⁺(aq) has decreased in oxidation number (gained electrons) and thus undergoes reduction, turning to Ag(s).
2Step 2: Identify the oxidizing and reducing agents
The oxidizing agent is Ag¹⁺(aq), and the reducing agent is Cu(s). The substance being oxidized is Cu(s), and the substance being reduced is Ag¹⁺(aq).
b.
3Step 3: Identify reaction type and changes in oxidation numbers
Checking the oxidation numbers for each element:
Cl: -1 -> -1
H: +1 -> +1
N: -3 -> -3
No change in oxidation numbers, hence, this is not an oxidation-reduction reaction.
c.
4Step 4: Identify reaction type and changes in oxidation numbers
Checking the oxidation numbers for each element:
Si: +4 -> +4
Cl: -1 -> -1
O: -2 -> -2
H: +1 -> +1
No change in oxidation numbers, hence, this is not an oxidation-reduction reaction.
d.
5Step 5: Identify reaction type and changes in oxidation numbers
Checking the oxidation numbers for each element:
Si: +4 -> 0
Mg: 0 -> +2
Cl: -1 -> -1
Si has decreased in oxidation number (gained electrons) and thus undergoes reduction, turning to Si(s). Mg undergoes oxidation, losing electrons, and having its oxidation number increase to form Mg²⁺(aq).
6Step 6: Identify the oxidizing and reducing agents
The oxidizing agent is SiCl₄(l), and the reducing agent is Mg(s). The substance being oxidized is Mg(s), and the substance being reduced is SiCl₄(l).
e.
7Step 7: Identify reaction type and changes in oxidation numbers
Checking the oxidation numbers for each element:
Al: +3 -> +3
O: -2 -> -2
H: +1 -> +1
No change in oxidation numbers, hence, this is not an oxidation-reduction reaction.
In conclusion, a and d are oxidation-reduction reactions, with the oxidizing agents being Ag¹⁺(aq) and SiCl₄(l), the reducing agents are Cu(s) and Mg(s), the substance being oxidized being Cu(s) and Mg(s), and the substance being reduced is Ag¹⁺(aq) and SiCl₄(l), respectively.
Key Concepts
Oxidation NumbersOxidizing AgentReducing AgentRedox Reaction
Oxidation Numbers
Oxidation numbers are a helpful way to track how electrons are transferred in a chemical reaction. Think of them as imaginary charges that help us figure out if an element has gained or lost electrons. In oxidation-reduction (redox) reactions, some elements will see a change in their oxidation numbers.
- If an element's oxidation number increases, this means it lost electrons, which is called oxidation.
- If an element's oxidation number decreases, it gained electrons, meaning it underwent reduction.
Oxidizing Agent
The oxidizing agent in a redox reaction is the substance that accepts electrons. It is reduced in the process, which means its oxidation number decreases.
- The oxidizing agent becomes reduced by taking electrons from another substance.
- It helps in oxidizing another element by gaining electrons itself.
- For example, in the reaction \( \mathrm{Cu}(s)+2 \mathrm{Ag}^{+}(a q) \rightarrow 2 \mathrm{Ag}(s)+\mathrm{Cu}^{2+}(a q) \), Ag+ ions are the oxidizing agents because they accept electrons from copper, reducing to Ag(s).
Reducing Agent
The reducing agent in a redox reaction is the substance that donates electrons. Its oxidation number increases as it is oxidized.
- The reducing agent is oxidized as it gives away electrons.
- It helps in reducing another substance by losing electrons itself.
- In the reaction \( \mathrm{Cu}(s)+2 \mathrm{Ag}^{+}(a q) \rightarrow 2 \mathrm{Ag}(s)+\mathrm{Cu}^{2+}(a q) \), copper is the reducing agent because it donates electrons to Ag+, becoming Cu2+.
Redox Reaction
A redox reaction, short for oxidation-reduction reaction, involves the transfer of electrons between substances.
- One substance is oxidized (loses electrons), while another is reduced (gains electrons).
- Identifying redox reactions involves looking for changes in oxidation numbers.
- Reactions such as \( \mathrm{Cu}(s)+2 \mathrm{Ag}^{+}(a q) \rightarrow 2 \mathrm{Ag}(s)+\mathrm{Cu}^{2+}(a q) \) are classic examples of redox processes.
Other exercises in this chapter
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