Problem 85
Question
Simplify each rational expression. $$ \frac{x+3}{3+x} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to 1, provided \(x \neq -3\).
1Step 1: Recognize the Problem
We are asked to simplify the rational expression \( \frac{x+3}{3+x} \). At first glance, it might seem as if the expression cannot be simplified.
2Step 2: Reinterpret the Expression
Observe that \( x + 3 \) and \( 3 + x \) are the same expression, since addition is commutative. Thus, \( x + 3 \) equals \( 3 + x \).
3Step 3: Identify Equivalent Expressions
Recognizing that \( x + 3 = 3 + x \), replace the denominator with \( x + 3 \). The expression becomes \( \frac{x+3}{x+3} \).
4Step 4: Simplify the Expression
Since \( x+3 \) is equal to the denominator if \( x+3 eq 0 \), \( \frac{x+3}{x+3} \) simplifies to \( 1 \). Note that this is valid only if the denominator is not zero, which means \( x eq -3 \).
5Step 5: State the Simplified Form
The rational expression \( \frac{x+3}{3+x} \) simplifies to \( 1 \) for all \( x eq -3 \).
Key Concepts
SimplificationCommutative PropertyEquivalent ExpressionsUndefined Values
Simplification
Simplification is a fundamental concept in mathematics, especially when dealing with rational expressions. A rational expression is simply a fraction where both the numerator and the denominator are polynomials. Simplifying a rational expression involves reducing it to its most basic form where no further factoring or reduction is possible.
In the given problem, the rational expression is \( \frac{x+3}{3+x} \). To simplify means to eliminate common factors from the numerator and the denominator so that the expression is as simple as possible. It is important to note that both terms in the numerator and the denominator must match exactly to perform this reduction.
In the given problem, the rational expression is \( \frac{x+3}{3+x} \). To simplify means to eliminate common factors from the numerator and the denominator so that the expression is as simple as possible. It is important to note that both terms in the numerator and the denominator must match exactly to perform this reduction.
- First, observe whether there is any factor common to both the numerator and the denominator. This deduction often involves reinterpreting and recognizing equivalent expressions, which we'll learn more about in the next sections.
- Once the equivalent nature is identified, the simplification can be applied, as in this exercise where the simplified form becomes \( 1 \).
Commutative Property
The commutative property is one of the basic properties of addition and multiplication that makes arithmetic readily manageable. It states that numbers can be added or multiplied in any order, and the result will be the same.
In mathematical terms:
This observation allows us to claim their equivalency, leading to efficient simplification. Understanding and applying fundamental properties like these can reveal underlying equivalences, streamlining various mathematical processes.
In mathematical terms:
- For addition, the commutative property states that \( a + b = b + a \).
- For multiplication, it implies \( ab = ba \).
This observation allows us to claim their equivalency, leading to efficient simplification. Understanding and applying fundamental properties like these can reveal underlying equivalences, streamlining various mathematical processes.
Equivalent Expressions
Equivalent expressions are expressions that, although they may look different at first glance, represent the same value in every context.
In algebra, identifying equivalent expressions is crucial, as it allows for simplification and easier comparison between mathematical formulas.
Using the commutative property, we identified that \( x + 3 \) and \( 3 + x \) are equivalent expressions in this exercise.
In algebra, identifying equivalent expressions is crucial, as it allows for simplification and easier comparison between mathematical formulas.
Using the commutative property, we identified that \( x + 3 \) and \( 3 + x \) are equivalent expressions in this exercise.
- This realization allows us to rewrite the denominator \( 3 + x \) as \( x + 3 \), which is identical to the numerator, thus facilitating further simplification.
Undefined Values
A crucial aspect to consider when working with rational expressions is the concept of undefined values. These occur in division when the denominator equals zero, since division by zero is undefined in mathematics.
For our simplified expression \( \frac{x+3}{x+3} \) which results in \( 1 \), we must always check what values of \( x \) would make the denominator zero.
Taking note of undefined values is essential in algebra to ensure the expressions and equations only include meaningful and real values.
For our simplified expression \( \frac{x+3}{x+3} \) which results in \( 1 \), we must always check what values of \( x \) would make the denominator zero.
- Here, setting \( x+3 = 0 \) gives us \( x = -3 \), pointing out that the expression is undefined at \( x = -3 \).
Taking note of undefined values is essential in algebra to ensure the expressions and equations only include meaningful and real values.
Other exercises in this chapter
Problem 83
Graph each logarithmic function. $$ f(x)=\log _{1 / 6} x $$
View solution Problem 84
Graph each logarithmic function. $$ f(x)=\log _{1 / 5} x $$
View solution Problem 86
Simplify each rational expression. $$ \frac{x-5}{5-x} $$
View solution Problem 87
Simplify each rational expression. $$ \frac{x^{2}-8 x+16}{2 x-8} $$
View solution