Problem 85
Question
In Exercises \(83-88,\) let \(\log _{b} 2=A\) and \(\log _{b} 3=\) C. Write each expression in terms of \(A\) and \(C\). $$ \log _{b} 8 $$
Step-by-Step Solution
Verified Answer
After completing the steps, the final answer to express \(\log _{b} 8\) in terms of \(A\) and \(C\) is \(3A\).
1Step 1: Breakdown of the Problem
In the given exercise, we are tasked to rewrite \(\log _{b} 8\) in terms of \(A\) and \(C\). One important thing to remember is that 8 can be expressed as a power of 2, specifically \(2^3\)
2Step 2: Apply logarithmic identities
Now that we've identified how 8 can be written in terms of 2, we can use one of the logarithmic identities, specifically the power rule. The power rule states that \(\log _{b} m^n = n \log _{b} m\). Thus, applying the rule gives: \(\log _{b} 8 = \log_{b} 2^3 = 3 \log_{b} 2\)
3Step 3: Final Interpretation
The final step is to simply replace \(\log _{b} 2\), which is given as \(A\) in the problem. Therefore, \(\log _{b} 8 = 3A\).
Key Concepts
Logarithmic IdentitiesChange of Base FormulaExponentsPower Rule
Logarithmic Identities
Logarithmic identities are essential rules that help us manipulate and understand logarithms better. They act like tools for simplifying complex logarithmic expressions. Let's have a quick review of the most common identities:
- Product Rule: \( \log_b (mn) = \log_b m + \log_b n \)
- Quotient Rule: \( \log_b \left( \frac{m}{n} \right) = \log_b m - \log_b n \)
- Power Rule: \( \log_b (m^n) = n \log_b m \)
Change of Base Formula
The change of base formula is a handy tool when dealing with logarithms of different bases. Sometimes, you encounter logarithms with a base that isn't very convenient for calculation, like a calculator that only provides logarithms base 10 or natural logarithms. The formula is:
This formula was not needed in the given exercise since the focus was on expressing the logarithm in terms of known values \( A \) and \( C \). Nevertheless, it's an efficient method for calculations when you're switching between different logarithmic bases.
- \( \log_b a = \frac{\log_k a}{\log_k b} \)
This formula was not needed in the given exercise since the focus was on expressing the logarithm in terms of known values \( A \) and \( C \). Nevertheless, it's an efficient method for calculations when you're switching between different logarithmic bases.
Exponents
Exponents are fundamental in mathematics since they describe repeated multiplication, similar to how logarithms describe repeated division. When you see something like \( 2^3 \), it means 2 multiplied by itself 3 times: \( 2 \times 2 \times 2 = 8 \).
In the given problem, recognizing that 8 can be expressed as \( 2^3 \) was pivotal. This understanding allowed us to use the power rule of logarithms effectively. Remember, when you see a number, think about whether it can be broken down into powers of known bases. This break down technique simplifies working with logarithms and exponents in solving mathematical problems.
In the given problem, recognizing that 8 can be expressed as \( 2^3 \) was pivotal. This understanding allowed us to use the power rule of logarithms effectively. Remember, when you see a number, think about whether it can be broken down into powers of known bases. This break down technique simplifies working with logarithms and exponents in solving mathematical problems.
Power Rule
The power rule of logarithms is a powerful and straightforward tool for simplifying logarithmic expressions involving exponents. The rule states that \( \log_b (m^n) = n \log_b m \). This means you can "bring down" the exponent as a multiplier in front of the logarithm, making it easier to work with.
In our solution, the power rule is what allowed us to transform \( \log_b 2^3 \) into \( 3 \log_b 2 \). This conversion turned a complex-looking logarithm into a simpler expression that could easily be translated into terms of \( A \). Understanding and applying this rule can help you unlock other scenarios where exponents are present inside logarithmic evaluations.
In our solution, the power rule is what allowed us to transform \( \log_b 2^3 \) into \( 3 \log_b 2 \). This conversion turned a complex-looking logarithm into a simpler expression that could easily be translated into terms of \( A \). Understanding and applying this rule can help you unlock other scenarios where exponents are present inside logarithmic evaluations.
Other exercises in this chapter
Problem 85
Evaluate or simplify each expression without using a calculator. $$ 10^{\log 33} $$
View solution Problem 85
Exercises \(83-85\) will help you prepare for the material covered in the first section of the next chapter. $$\text { Solve: } 5(2 x-3)-4 x-9$$
View solution Problem 85
Solve each logarithmic equation in Exercises \(49-92 .\) Be sure to reject any value of \(x\) that is not in the domain of the original logarithmic expressions.
View solution Problem 85
I'm using a photocopier to reduce an image over and over by \(50 \%,\) so the exponential function \(f(x)-\left(\frac{1}{2}\right)^{x}\) models the new image si
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