Problem 85
Question
If \(g_{E}\) and \(g_{m}\) are the accelerations due to gravity on the surfaces of the earth and moon respectively and if Millikan's oil drop experiment and the performed on the two surfaces one will be find the ratio \(=\frac{\text { electronic charge on the moon }}{\text { electronic charge on the earth }}\) to be (a) 1 (b) 0 (c) \(\frac{g_{E}}{g_{m}}\) (d) \(\frac{g_{m}}{g_{E}}\)
Step-by-Step Solution
Verified Answer
The ratio is 1, as electronic charge is the same everywhere.
1Step 1: Understanding the Problem
We need to find the ratio of the electronic charge on the moon to the electronic charge on the earth from Millikan's oil drop experiment conducted on both surfaces. We have four choices.
2Step 2: Analyzing Millikan’s Experiment
In Millikan's oil drop experiment, the electronic charge measured, denoted by \( e \), is a fundamental constant. This means that \( e \) does not change regardless of the location, whether on Earth or the moon.
3Step 3: Applying the Concept of Fundamental Charge
Since the electronic charge \( e \) is constant at any point in the universe, the ratio of the electronic charge on the moon to the electronic charge on the earth is given by \( \frac{e_{\text{moon}}}{e_{\text{earth}}} = \frac{e}{e} = 1 \).
4Step 4: Conclusion: Final Answer
The ratio \( \frac{e_{\text{moon}}}{e_{\text{earth}}} \) is therefore 1. This means the electronic charge does not depend on the gravitational field where the experiment is conducted.
Key Concepts
Electronic ChargeGravityAcceleration Due to GravityComparison of Gravitational Effects
Electronic Charge
Electronic charge is a fundamental property of particles, often associated with protons, electrons, and other subatomic particles. The basic unit of electronic charge, identified as \( e \), has a fixed magnitude of approximately \( 1.6 \times 10^{-19} \) coulombs for an electron. This constant remains unchanged irrespective of any external conditions, such as the gravitational field or location.
- Electronic charge is a constant; it doesn’t vary from one location to another, such as between the Earth and the Moon.
- In Millikan's oil drop experiment, electronic charge was measured to be the same on all Earth-like tests.
- Because of its constant nature, the ratio of electronic charge on the Moon to that on Earth remains \( 1 \).
Gravity
Gravity is a natural force through which objects with mass attract each other. On Earth, the gravitational force attracts objects towards the center with an acceleration known as acceleration due to gravity. The strength of gravity can vary depending on the celestial body, such as Earth or the Moon.
- Gravity is responsible for the weight of objects.
- On Earth, gravity provides an acceleration of ≈ \(9.81\,\text{m/s}^2\).
- The gravitational forces are weaker on the Moon, causing objects to weigh less.
Acceleration Due to Gravity
Acceleration due to gravity refers to the rate at which objects accelerate towards the center of a celestial body because of the gravitational force. It is denoted by \( g \). It varies across different planets and celestial bodies. For instance, the Moon has a much lower gravitational pull than Earth.
- On Earth, \( g_E = 9.81\,\text{m/s}^2\).
- On the Moon, acceleration due to gravity is approximately one-sixth that of Earth's, known as \( g_m \) ≈ \( 1.63\,\text{m/s}^2\).
- The differences in acceleration create variations in weight measurements of the same object on different celestial bodies.
Comparison of Gravitational Effects
Comparing the gravitational effects on different celestial bodies helps us understand how mass and gravity interact. When conducting experiments like Millikan's oil drop, this comparison becomes essential to identify what factors affect the outcomes and what remains consistent.
- On Earth, gravity is stronger, influencing the fall speed of objects.
- On the Moon, the weaker gravitational force results in slower falls.
- Nonetheless, these differences in gravity do not influence the electronic charge value in any location.
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