Problem 85
Question
Either factor out the greatest common factor or factor by grouping. $$ a x+2 y+a y+2 x $$
Step-by-Step Solution
Verified Answer
(a + 2)(x + y)
1Step 1: Group the terms
Group the expression into pairs to make it easier to factor. So, you will group \(a x\) with \(a y\) and \(2 y\) with \(2 x\). This gives: \[ (a x + a y) + (2 y + 2 x) \]
2Step 2: Factor out the common factors in each group
In the first group \(a x + a y\), factor out \(a\). In the second group \(2 y + 2 x\), factor out \(2\). This gives: \[ a (x + y) + 2 (y + x) \]
3Step 3: Combine the like terms
Notice that \(x + y\) and \(y + x\) are the same. Since \((x + y) = (y + x)\), you can factor out \((x + y)\). This gives: \[ (a + 2)(x + y) \]
Key Concepts
greatest common factorfactoring by groupingalgebraic expressionspolynomial factorization
greatest common factor
The greatest common factor (GCF) is the largest number or algebraic expression that divides each term in a polynomial without leaving a remainder. To find the GCF of algebraic terms, identify the common elements in each term and select the lowest power of common variables and constants.
For example, in the expression \(ax + ay\), both terms share the factor \(a\). Thus, \(a\) is the GCF.
For example, in the expression \(ax + ay\), both terms share the factor \(a\). Thus, \(a\) is the GCF.
- Step 1: Identify the common factor in each term (e.g., \(a\) in \(ax\) and \(ay\)).
- Step 2: Factor out the GCF from the expression: \(a(x + y)\).
factoring by grouping
Factoring by grouping is a method used when a polynomial has four or more terms. It involves grouping the terms in pairs and factoring out common factors in each group.
Consider the example: \(ax + 2y + ay + 2x\).
Here are the steps:
Consider the example: \(ax + 2y + ay + 2x\).
Here are the steps:
- Step 1: Group the terms: \((ax + ay) + (2y + 2x)\).
- Step 2: Factor out the common factors in each group: \(a(x + y) + 2(y + x)\).
- Step 3: Notice that \(x + y\) and \(y + x\) are the same. Factor out \((x + y)\): \((a + 2)(x + y)\).
algebraic expressions
Algebraic expressions are combinations of variables, constants, and operations (addition, subtraction, multiplication, and division). Understanding them is crucial for solving and factoring polynomials.
Take the expression \(ax + 2y + ay + 2x\). Each term is formed by a coefficient (a constant or variable) multiplied by a variable (e.g., \(ax\) where \(a\) is the coefficient and \(x\) is the variable).
Take the expression \(ax + 2y + ay + 2x\). Each term is formed by a coefficient (a constant or variable) multiplied by a variable (e.g., \(ax\) where \(a\) is the coefficient and \(x\) is the variable).
- Terms: The individual parts separated by plus or minus signs (\(ax\), \(2y\), \(ay\), \(2x\)).
- Coefficients: Numbers or variables multiplying the variable (\(a\), \(2\)).
- Variables: Symbols representing unknown values (\(x\), \(y\)).
polynomial factorization
Polynomial factorization is the process of breaking down a polynomial into simpler factors that, when multiplied together, give the original polynomial. This technique is vital in solving polynomial equations and simplifying expressions.
To factor the polynomial \(ax + 2y + ay + 2x\), follow these steps:
To factor the polynomial \(ax + 2y + ay + 2x\), follow these steps:
- Step 1: Group the terms to find common factors: \((ax + ay) + (2y + 2x)\).
- Step 2: Factor out the common factors in each group: \(a(x + y) + 2(y + x)\).
- Step 3: Recognize that \(x + y\) and \(y + x\) are the same: \((x + y)\).
- Step 4: Factor \((x + y)\) from each group: \((a + 2)(x + y)\).
Other exercises in this chapter
Problem 85
In this section, the difference of squares pattern is \(a^{2}-b^{2}=(a+b)(a-b)\). We can rewrite this pattern as \(a^{2}-b^{2}=(a-b)(a+b)\). What property of th
View solution Problem 85
A standard rectangular city block in Manhattan is about \(264 \mathrm{ft}\) by \(900 \mathrm{ft}\). One acre of land is \(43,560 \mathrm{ft}^{2}\). Find the siz
View solution Problem 86
Factor completely. Identify any prime polynomials. $$ 2 n^{6}+4 n^{3} p^{2}+2 p^{4} $$
View solution Problem 86
We can write the difference of squares pattern as \(a^{2}-b^{2}=(a+b)(a-b)\) or as \(a^{2}-b^{2}=\) \((a-b)(a+b)\). Show that \((a+b)(a-b)=\) \((a-b)(a+b)\).
View solution