Problem 85
Question
Consider two identical \(1-\mathrm{L}\) containers, both at room temperature \((300 \mathrm{~K})\). One of them contains 1 mole of helium gas, and the other contains 1 mole of hydrogen gas. Is the pressure higher in the helium container, higher in the hydrogen container, or the same in the two containers?
Step-by-Step Solution
Verified Answer
The pressures in both the helium and hydrogen containers are the same, as per the Ideal Gas Law \(PV = nRT\), because they have equal volume (1 L), equal number of moles (1 mole), and equal temperature (300 K). The formula results in equal pressure values for both containers: \(P_{He} = P_{H2} = \frac{1mol \times R \times 300K}{1L}\).
1Step 1: Ideal Gas Law Formula
First, we need to understand the Ideal Gas Law formula:
\(PV = nRT\)
where:
- P is the gas pressure,
- V is the gas volume,
- n is the number of moles of the gas,
- R is the ideal gas constant, and
- T is the gas temperature in Kelvin.
2Step 2: Compare the Gases
In our case, we have the following information for both helium and hydrogen gases:
- V (volume) = 1 L
- n (number of moles) = 1 mole
- T (temperature) = 300 K
And the ideal gas constant, R, is the same for all ideal gases. So, our comparison should be based only on the pressure (P), as all other values are equal.
3Step 3: Plug Values into the Formula
For helium gas (He):
\(P_{He} \times 1L = 1mol \times R \times 300K\)
\(P_{He} = \frac{1mol \times R \times 300K}{1L}\)
For hydrogen gas (H₂):
\(P_{H2} \times 1L = 1mol \times R \times 300K\)
\(P_{H2} = \frac{1mol \times R \times 300K}{1L}\)
4Step 4: Compare Pressures
Now let's compare the pressures:
\(P_{He} = P_{H2} = \frac{1mol \times R \times 300K}{1L}\)
Since both pressures are equal, we can conclude that:
Pressures in both helium and hydrogen containers are the same.
Key Concepts
Pressure ComparisonHelium GasHydrogen GasGas Constant
Pressure Comparison
In the exploration of the ideal gas law, comparing pressures involves understanding how different gases behave under identical conditions, such as temperature and volume. Here, we are dealing with two gases, helium and hydrogen, in identical containers at the same temperature of 300 Kelvin and a fixed volume of 1 liter. The number of moles for both gases is also equivalent, set at 1 mole each. Using the ideal gas law, \(PV = nRT\), the only variable left that could differ between these two scenarios is usually pressure. However, if all other parameters are the same, then the pressure must also be the same.
- Both containers have the same volume: 1 L
- Temperature outside and inside matches: 300 K
- Each gas contains exactly 1 mole
Helium Gas
Helium gas is a noble gas, part of a group of gases that are known for being very stable and unreactive. Its stability makes it a prime candidate for usage in various scientific applications.
- Helium molecules are monoatomic, meaning each molecule consists of a single atom
- Due to being a light gas, it often has a lower density compared to more complex molecules
Hydrogen Gas
Hydrogen gas is the simplest and lightest element, consisting of molecules that are diatomic, meaning each molecule is composed of two hydrogen atoms (H₂). This diatomic nature doesn't change the application of the ideal gas law; all ideal gases behave similarly under the law if conditions such as temperature, volume, and moles remain constant.
- Hydrogen is highly flammable and reactive, hence it’s used in fuel cells and industry
- Diatomic hydrogen has more internal energy states compared to monoatomic gases
Gas Constant
The gas constant, denoted as \(R\), is a crucial constant in the ideal gas equation. It serves as the linchpin ensuring that comparisons between different gases remain valid when using the ideal gas law. The gas constant has the same value for all ideal gases, meaning that it unifies the equation.
- It bridges the relationship between energy (as seen in temperature), volume, and pressure
- Its consistent value enables broad applications of the ideal gas law across various gases
Other exercises in this chapter
Problem 83
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