Problem 85
Question
At the north campus of a performing arts school, \(10 \%\) of the students are music majors. At the south campus, \(90 \%\) of the students are music majors. The campuses are merged into one east campus. If \(42 \%\) of the 1000 students at the east campus are music majors, how many students did the north and south campuses have before the merger?
Step-by-Step Solution
Verified Answer
Before the merger, the north campus had 600 students and the south campus had 400 students.
1Step 1: Establish the system of equations
Let's say that the number of students in the north campus is \(N\) and the number of students in the south campus is \(S\). We know that \(N + S = 1000\), because the total number of students is 1000. Additionally, the percentage of music students in the north and south campuses when merged together is 42%, or 420 students. We can state this as \(0.10N + 0.90S = 420\). This gives us a second equation.
2Step 2: Solve the system of equations
We can solve this system of equations either by substitution or elimination. However, since none of the equations have been solved for either variable, using elimination would be easier. Multiply the first equation by 0.10 and the second equation by 1 to eliminate \(N\): \n\n0.10N + 0.10S = 100 \n0.10N + 0.90S = 420 \n\nSubtracting these two equations gives: \n0.80S = 320 \n\nSo, \(S = 400\). Substituting \(S = 400\) into the equation \(N + S = 1000\) gives \(N = 600\)
3Step 3: Conclusion
Therefore, before the merger, the north campus had 600 students, and the south campus had 400 students.
Key Concepts
Systems of EquationsPercentagesMathematical Reasoning
Systems of Equations
When tackling an algebra word problem, especially one involving mixing percentages, systems of equations are a reliable method for finding the solution. A system of equations involves more than one equation that shares common variables. To solve the word problem about the performing arts school, two equations are established from the given data:
- The total number of students at both campuses is 1000, giving us the equation: \( N + S = 1000 \)
- The second equation comes from the percentage of music students in each campus: \( 0.10N + 0.90S = 420 \). This equation is derived from figuring out how the percentages at north and south contribute to the total music students.
Percentages
Percentages are a critical aspect of this problem and many real-world scenarios. They represent a fraction of 100 and are used to express proportions and comparisons between different quantities. In this exercise, we deal with converting the percentage of music majors into actual numbers.
- The north campus has \(10\%\) music majors, meaning \(0.10 \times N\).
- The south campus has \(90\%\) music majors, represented as \(0.90 \times S\).
Mathematical Reasoning
Mathematical reasoning is the logical thought process that helps solve problems. In problems involving systems of equations, knowing how to translate word problems into mathematical expressions is crucial. With the problem at hand, step-by-step reasoning is needed to interpret the percentages and their effects.
Firstly, create clear variables for unknowns, such as \(N\) for north campus and \(S\) for south campus students. This helps in visualizing the problem. Then, understand the role of each percentage. The reasoning process allows us to deduce relationships between variables and set up the equations.
Using mathematical reasoning, you then determine the best way to solve the equations, choosing between substitution or elimination. This reasoning not only finds solutions but also helps verify that those solutions make sense (for instance, checking that 600 and 400 add up to 1000 confirms the calculations). Developing strong reasoning skills aids in methodically approaching any word problem, ensuring accurate solutions.
Firstly, create clear variables for unknowns, such as \(N\) for north campus and \(S\) for south campus students. This helps in visualizing the problem. Then, understand the role of each percentage. The reasoning process allows us to deduce relationships between variables and set up the equations.
Using mathematical reasoning, you then determine the best way to solve the equations, choosing between substitution or elimination. This reasoning not only finds solutions but also helps verify that those solutions make sense (for instance, checking that 600 and 400 add up to 1000 confirms the calculations). Developing strong reasoning skills aids in methodically approaching any word problem, ensuring accurate solutions.
Other exercises in this chapter
Problem 84
Solve each equation in Exercises \(83-108\) by the method of your choice. $$ 3 x^{2}-4 x=4 $$
View solution Problem 84
Absolute value expressions are equal when the expressions inside the absolute value bars are equal to or opposites of each other. (graph cannot copy for a,b,c,d
View solution Problem 85
Solve each equation in Exercises \(83-108\) by the method of your choice. $$ 5 x^{2}+2=11 x $$
View solution Problem 85
Find all values of \(x\) satisfying the given conditions. $$y=|5-4 x| \text { and } y=11$$
View solution