Problem 845
Question
A stress of \(3.18 \times 10^{8} \mathrm{Nm}^{2}\) is applied to steel rod of length \(1 \mathrm{~m}\) along its length. Its young's modulus is \(2 \times 10^{11}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\) Then what is the elongation produced in the rod in \(\mathrm{mm}\) ? (A) \(3.18\) (B) \(6.36\) (C) \(5.18\) (D) \(1.59\)
Step-by-Step Solution
Verified Answer
The elongation produced in the rod is \(1.59 \mathrm{mm}\).
1Step 1: Write down Hooke's Law formula
Hooke's Law relates stress (σ), Young's modulus (E), and strain (ε) in the following way:
\(σ = Eε\)
2Step 2: Calculate the strain
Using Hooke's Law formula, we can find the strain (ε) produced in the steel rod:
\(\epsilon = \frac{\sigma}{E}\)
Plug in the given values for stress and Young's modulus:
\( ε = \frac{3.18 \times 10^{8} \mathrm{Nm}^{2}}{2 \times 10^{11}\left(\mathrm{N} / \mathrm{m}^{2}\right)}\)
3Step 3: Solve for strain
Calculate the strain (ε) by dividing the stress by the Young's modulus:
\(ε = \frac{3.18 \times 10^{8}}{2 \times 10^{11}}\)
After the calculation, we get:
\(ε = 1.59 \times 10^{-3}\)
4Step 4: Calculate elongation
Since strain (ε) is dimensionless and represents the ratio of elongation produced by the initial length, we can use it to find the elongation (ΔL) of the steel rod:
\(ΔL = ε \times L\)
Plug in the given length of the steel rod and the calculated strain:
\(ΔL = (1.59 \times 10^{-3}) \times (1 \mathrm{m})\)
5Step 5: Convert elongation to millimeters
Calculate the elongation (ΔL) produced in the rod in meters:
\(ΔL = 1.59 \times 10^{-3} \mathrm{m}\)
To convert the elongation to millimeters, multiply by 1000:
\(ΔL = 1.59 \times 10^{-3} \mathrm{m} \times 1000\)
Which gives us the final answer in millimeters:
\(ΔL = 1.59 \mathrm{mm}\)
Therefore, the elongation produced in the rod is 1.59 mm, and the correct answer is (D).
Key Concepts
Hooke's LawStrainStressElongation
Hooke's Law
Hooke's Law is a fundamental principle in physics that explains how materials respond to stress and strain. It provides a simple linear relationship among stress (force per unit area), strain (deformation per unit length), and the material's Young's modulus (a measure of stiffness). Broadly speaking, Hooke's Law can be summarized by the formula:
- \(\sigma = E \epsilon\), where \( \sigma\) is stress, \( E\) is Young's modulus, and \( \epsilon \) is strain.
Strain
Strain is a measure of how much an object deforms under stress. Essentially, it describes the extent of deformation in the object's shape or size. Strain is calculated by the formula:
- \( \epsilon = \frac{\Delta L}{L} \), where \( \Delta L \) is the change in length and \( L \) is the original length.
Stress
Stress is defined as the internal force exerted by a material per unit area opposing an external force. It quantifies the intensity of the internal forces acting within a deformed body. Stress can be calculated using the formula:
- \( \sigma = \frac{F}{A} \), where \( F \) is the force applied and \( A \) is the cross-sectional area.
Elongation
Elongation is the change in length that occurs as a material is stretched under stress. It represents how much longer a material becomes when a pulling force is applied. The relationship between elongation and strain is straightforward:
- \( \Delta L = \epsilon \times L \), where \( \Delta L \) is the elongation, \( \epsilon \) is the strain, and \( L \) is the original length.
Other exercises in this chapter
Problem 841
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