Problem 84
Question
Write an equation for each parabola with vertex at the origin. Through \((3,2) ;\) symmetric with respect to the \(x\) -axis
Step-by-Step Solution
Verified Answer
The equation is \(y^2 = \frac{4}{3}x\).
1Step 1: Identify Parabola's Orientation
Since the parabola is symmetric with respect to the \(x\)-axis and has its vertex at the origin, the parabola must open left or right. This indicates that the equation of the parabola will be of the form \(y^2 = 4px\) or \(y^2 = -4px\).
2Step 2: Determine the Formula for the Parabola
Given that the parabola passes through the point \((3,2)\), we will test the equation form \(y^2 = 4px\).
3Step 3: Substitute Coordinates to Find 'p'
Substitute \((x, y) = (3, 2)\) into the equation \(y^2 = 4px\). This gives us: \(2^2 = 4p(3)\).
4Step 4: Solve for 'p'
Simplify the equation from Step 3: \(4 = 12p\). Divide both sides by 12 to find \(p = \frac{1}{3}\).
5Step 5: Write the Final Equation
Now that \(p = \frac{1}{3}\), substitute \(p\) back into the equation \(y^2 = 4px\) to write the final equation for the parabola: \(y^2 = \frac{4}{3}x\).
Key Concepts
VertexSymmetryCoordinate GeometrySolving Equations
Vertex
The vertex is a crucial point of a parabola, acting as its midpoint or the point where it turns. In "vertex form," the equation of a parabola is typically shown with
- A vertex at the origin, written as \[(h, k) = (0, 0),\]resulting in simple formulations.
- For the parabola opening left or right, the equation becomes \[y^2 = 4px.\]
- When a parabola's vertex is at the origin, solving becomes simpler as there are no horizontal or vertical shifts.
Symmetry
Symmetry refers to how one side of the parabola mirrors the other. For a parabola symmetric with respect to the x-axis:
- This symmetry means that for every point \((x, y),\)there's a corresponding point \((x, -y)\).
- The equation \[y^2 = 4px\]indicates this symmetrical nature.
Coordinate Geometry
Coordinate geometry, or analytic geometry, enables us to study geometrical shapes in a numerical way. When dealing with parabolas:
- You need points like \((3,2)\)to find key characteristics such as the value 'p' in the parabola equation \[y^2 = 4px.\]
- Using these points in an equation showcases how coordinate geometry mixes algebra with geometry.
Solving Equations
Solving parabola equations involves substituting known values into the general form and solving for unknowns:
- Substitute the point \((3,2)\) into \[y^2 = 4px\] which helps in finding unknown constants like 'p'.
- Begin by plugging in \((3, 2)\). This results in solving for 'p' with calculations like \[4 = 12p,\]leading to \[p = \frac{1}{3}.\]
- Solve incrementally, focusing on each part of the equation step by step.
- Finally, rewrite the equation with the found values, \[y^2 = \frac{4}{3}x,\]representing the parabola.
Other exercises in this chapter
Problem 83
Graph the solution set of each system of inequalities by hand. $$\begin{array}{c} 4 x^{2}-y^{2}>4 \\ 9 x^{2}+4 y^{2}>36 \end{array}$$
View solution Problem 84
Write the equation in standard form for a hyperbola centered at ( \(h, k\) ). Identify the center and vertices. \(5 x^{2}+10 x-7 y^{2}+28 y=58\)
View solution Problem 84
Graph the solution set of each system of inequalities by hand. $$\begin{aligned} &16 x^{2}+9 y^{2}1 \end{aligned}$$
View solution Problem 85
For individual or group investigation. Consider the ellipse and hyperbola defined by $$\frac{x^{2}}{16}+\frac{y^{2}}{12}=1 \quad \text { and } \quad \frac{x^{2}
View solution