Problem 84
Question
Solve equation by the method of your choice. $$ 3 x^{2}-4 x=4 $$
Step-by-Step Solution
Verified Answer
The solutions of the equation \(3x^{2}-4x-4=0\) are \(x=2\) and \(x=-\frac{2}{3}\).
1Step 1: Rewrite Equation as Standard Form
Start by re-writing the standard form \(ax^{2}+bx+c=0\), so \[3x^{2}-4x-4 = 0\] this will make applying the quadratic formula easier.
2Step 2: Apply Quadratic Formula
Once you have the equation in standard form with \(a=3\), \(b=-4\), and \(c=-4\), you can apply the quadratic formula \(\frac{-b±\sqrt{b^{2}-4ac}}{2a}\), which will solve for \(x\). The formula will look like this: \[x=\frac{-(-4) \pm \sqrt{(-4)^{2}-4*3*(-4)}}{2*3}\]
3Step 3: Simplify Inside of the Square Root
Before proceeding with solving the equation, simplify the calculations inside the square root: \(16+48=64\). Then replace it back into the equation \[x=\frac{4±\sqrt{64}}{6}\].
4Step 4: Solve for X
After you've simplified the square root, perform the final calculations, which gives you two potential answers for \(x\), using plus and minus operators: \[x=\frac{4+8}{6}=2\] and \[x=\frac{4-8}{6}=-\frac{2}{3}\]
Key Concepts
Understanding Quadratic EquationsTransforming to Standard FormSolving Equations Using the Quadratic Formula
Understanding Quadratic Equations
A quadratic equation is an essential concept in algebra. It's a type of polynomial equation distinguished by the highest power of its variable being 2. This gives the equation a characteristic curve shape known as a parabola when graphed. A basic quadratic equation is typically written as:
- \(ax^2 + bx + c = 0\)
- \(a\): coefficient of \(x^2\), it cannot be zero.
- \(b\): coefficient of \(x\).
- \(c\): constant term.
Transforming to Standard Form
To effectively solve a quadratic equation, it's helpful to rewrite it in its standard form: \(ax^2 + bx + c = 0\). This rearrangement creates a clearer path for applying mathematical methods, such as completing the square or using the quadratic formula. Let's take an example:Given the equation: \(3x^2 - 4x = 4\),First, move all terms to one side of the equation to set it to zero:
- Subtract 4 from both sides: \(3x^2 - 4x - 4 = 0\)
Solving Equations Using the Quadratic Formula
The quadratic formula provides a straightforward method to find solutions to any quadratic equation. When the equation is in standard form \(ax^2 + bx + c = 0\), the quadratic formula is given by:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Using this formula involves several important steps:
- Calculate the values of \(b^2 - 4ac\), known as the discriminant.
- The discriminant helps determine the nature of the roots.
- Solve for \(x\) by simplifying the expression.
- Here, \(a = 3\), \(b = -4\), and \(c = -4\).
- First compute the discriminant: \((-4)^2 - 4 \cdot 3 \cdot (-4) = 64\).
- Next, substitute these into the formula: \(x = \frac{4 \pm \sqrt{64}}{6}\).
- This results in the solutions \(x = 2\) and \(x = -\frac{2}{3}\).
Other exercises in this chapter
Problem 83
Solve equation by the method of your choice. $$ 2 x^{2}-x=1 $$
View solution Problem 84
In Exercises 59–94, solve each absolute value inequality. $$ -2|5-x|
View solution Problem 85
In Exercises 59–94, solve each absolute value inequality. $$ 3 \leq|2 x-1| $$
View solution Problem 85
Solve equation by the method of your choice. $$ 5 x^{2}+2=11 x $$
View solution