Problem 84
Question
Refer to the following: According to the \(n\) th root theorem, the first of the \(n\) th roots of the complex number \(z=r(\cos \theta+i \sin \theta)\) is given by \(w_{1}=r^{1 / n}\left[\cos \left(\frac{\theta}{n}+\frac{2 \pi}{n}\right)+i \sin \left(\frac{\theta}{n}+\frac{2 \pi}{n}\right)\right],\) with \(\theta\) in radians or \(w_{1}=r^{1 / n}\left[\cos \left(\frac{\theta}{n}+\frac{360^{\circ}}{n}\right)+i \sin \left(\frac{\theta}{n}+\frac{360^{\circ}}{n}\right)\right]\) with \(\theta\) in degrees. Using the graphing calculator to plot the \(n\) roots of a complex number \(z,\) enter \(r_{1}=r, \theta \min =\frac{\theta}{n}, \theta \max =2 \pi+\frac{\theta}{n}\) or \(360^{\circ}+\frac{\theta}{n}, \theta\) step \(=\frac{2 \pi}{n}\) or \(\frac{360^{\circ}}{n}, \mathrm{xmin}=-r, \mathrm{xmax}=r\) ymin \(=-r,\) ymax \(=r,\) and \([\mathrm{MODE}]\) in radians or degrees. Find the fourth roots of \(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2} i,\) and plot the roots with a calculator.
Step-by-Step Solution
VerifiedKey Concepts
Complex Numbers
For example, the complex number \( -\frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2}i \) has a real part \( -\frac{\sqrt{2}}{2} \) and an imaginary part \( \frac{\sqrt{2}}{2}i \). Its position on the complex plane is determined by these components. Understanding complex numbers is crucial for exploring operations such as addition, subtraction, multiplication, and particularly root extraction in cases involving imaginary components, as highlighted in the nth root theorem.
Polar Form
Where:
- \( r \) is the modulus or magnitude of the complex number, representing the distance from the origin to the point on the complex plane.
- \( \theta \) is the argument, which is the angle between the positive real axis and the line representing the complex number in the plane.
Using polar form simplifies many operations. For instance, rotating or scaling a vector becomes straightforward when calculated in polar form. In our example, the complex number \(-\frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2}i\) converts to polar form as \(1(\cos \frac{3\pi}{4} + i \sin \frac{3\pi}{4})\) because it lies on the unit circle (distance equals one), with an angle of \(\frac{3\pi}{4}\) radians from the positive x-axis.
Graphing Calculator
Here's how you can set up your graphing calculator to plot complex numbers like the fourth roots of our given complex number:
- Switch the calculator to 'polar mode' for plotting complex conjugates.
- Ensure it is in 'radians mode' if you're working with radian measures for precision.
- Set \( r = 1 \) owing to the magnitude found earlier.
- Define \( \theta \min \) and \( \theta \max \) to cover the complete unit circle with increments to capture each root evenly.
- Bound your graph within a range, say \([-1, 1]\) for both axes, to capture the unit circle visually.
Modulus and Argument
In our specific example, the modulus is \( 1 \), stemming from \( \sqrt{\left(-\frac{\sqrt{2}}{2}\right)^2 + \left(\frac{\sqrt{2}}{2}\right)^2} = 1 \).
The argument \( \theta \) is the angle of rotation from the positive real axis to the line representing the complex number, measured in radians or degrees. It is crucial for expressing the direction of the complex number. For the given complex number, the argument, after adjusting for its position in the second quadrant, is \( \frac{3\pi}{4} \) radians, allowing the further conversion to polar form and exploration of roots.