Problem 84
Question
Gas Mileage The gas mileage \(g\) (measured in mi/gal) for a particular vehicle, driven at \(v\) mi/h, is given by the formula \(g=10+0.9 v-0.01 v^{2},\) as long as \(v\) is between 10 mi/h and 75 \(\mathrm{mi} / \mathrm{h}\) . For what range of speeds is the vehicle's mileage 30 \(\mathrm{mi} / \mathrm{gal}\) or better?
Step-by-Step Solution
Verified Answer
The vehicle's mileage is 30 mi/gal or better between 40 and 50 mi/h.
1Step 1: Understand the Problem
We need to find the range of speeds for which gas mileage \( g \) is at least 30 mi/gal, using the given function \( g = 10 + 0.9v - 0.01v^2 \). The speed \( v \) must be between 10 mi/h and 75 mi/h.
2Step 2: Set Up the Inequality
To find the range of speeds where the gas mileage is at least 30 mi/gal, we need to solve the inequality \( 10 + 0.9v - 0.01v^2 \geq 30 \).
3Step 3: Rearrange the Inequality
Subtract 30 from both sides to set the inequality to zero: \( 10 + 0.9v - 0.01v^2 - 30 \geq 0 \), which simplifies to \( -0.01v^2 + 0.9v - 20 \geq 0 \).
4Step 4: Solve the Quadratic Inequality
Solve the quadratic equation \( -0.01v^2 + 0.9v - 20 = 0 \) using the quadratic formula. The formula is \( v = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) where \( a = -0.01 \), \( b = 0.9 \), and \( c = -20 \).
5Step 5: Calculate the Discriminant
Calculate the discriminant \( \Delta = b^2 - 4ac = (0.9)^2 - 4(-0.01)(-20) = 0.81 - 0.8 = 0.01 \). Since \( \Delta > 0 \), the equation has two distinct solutions.
6Step 6: Find the Roots
Substitute into the quadratic formula: \( v = \frac{-0.9 \pm \sqrt{0.01}}{-0.02} \). Calculate the roots: \( v = \frac{-0.9 + 0.1}{-0.02} = 40 \) and \( v = \frac{-0.9 - 0.1}{-0.02} = 50 \).
7Step 7: Determine the Range of Speeds
The solutions \( v = 40 \) and \( v = 50 \) split the number line into intervals. Since the quadratic function opens downwards (\( a < 0 \)), \( g \geq 30 \) in the interval \( 40 \leq v \leq 50 \), ensuring the vehicle's mileage is 30 mi/gal or better.
Key Concepts
Gas MileageQuadratic FormulaRange of Speeds
Gas Mileage
Gas mileage refers to how efficiently a vehicle uses fuel, typically measured in miles per gallon (mi/gal). Understanding gas mileage can help determine the most economical speed range for driving. In this exercise, we are given a mathematical function of gas mileage expressed as:
For gas mileage to reach a certain level, such as 30 mi/gal or more, it is necessary to solve the inequality derived from this relationship. Knowing the mileage efficiency helps drivers optimize their trips for fuel use, saving both money and energy in the process.
Speeds between 40 mi/h and 50 mi/h provide the best efficiency according to the calculations, so driving within this range can maximize gas mileage.
- \(g = 10 + 0.9v - 0.01v^2\)
For gas mileage to reach a certain level, such as 30 mi/gal or more, it is necessary to solve the inequality derived from this relationship. Knowing the mileage efficiency helps drivers optimize their trips for fuel use, saving both money and energy in the process.
Speeds between 40 mi/h and 50 mi/h provide the best efficiency according to the calculations, so driving within this range can maximize gas mileage.
Quadratic Formula
The quadratic formula is a powerful tool used to solve equations of the form \( ax^2 + bx + c = 0 \). Understanding this formula is essential, especially when dealing with quadratic equations like the one in our exercise:
In this exercise, the discriminant \( b^2 - 4ac \) was calculated to find whether real solutions exist. A positive discriminant, \(0.01\) in this case, indicates two distinct real roots. These roots help in determining the specific speeds that keep the vehicle's mileage at or above your given target. Mastering this formula is crucial to solving similar real-world problems effectively.
- \(-0.01v^2 + 0.9v - 20 = 0\)
- \(v = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
In this exercise, the discriminant \( b^2 - 4ac \) was calculated to find whether real solutions exist. A positive discriminant, \(0.01\) in this case, indicates two distinct real roots. These roots help in determining the specific speeds that keep the vehicle's mileage at or above your given target. Mastering this formula is crucial to solving similar real-world problems effectively.
Range of Speeds
Identifying the range of speeds that optimize fuel efficiency involves understanding both the quadratic expression and its solutions. With the quadratic formula solved, the roots obtained were \( v = 40 \) and \( v = 50 \). These speeds effectively mark the boundaries for the vehicle achieving at least 30 mi/gal.
In simpler terms, these boundaries help to establish intervals. In this case, since the parabola opens downwards (indicated by \(a < 0 \)), the mileage is greatest between the roots. Therefore,
In simpler terms, these boundaries help to establish intervals. In this case, since the parabola opens downwards (indicated by \(a < 0 \)), the mileage is greatest between the roots. Therefore,
- Speeds from \(40\) mi/h to \(50\) mi/h give the desired gas mileage.
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