Problem 84
Question
Factor completely. $$64 c^{3}+1$$
Step-by-Step Solution
Verified Answer
The factored form of the given expression is \((4c + 1)(16c^2 - 4c + 1)\).
1Step 1: Rewrite the expression as sum of cubes
First, we need to rewrite the expression as a sum of cubes:
\(64c^3 + 1 = (4c)^3 + 1^3\)
2Step 2: Applying the sum of cubes formula
The sum of cubes formula is: \(a^3 + b^3 = (a+b)(a^2 - ab + b^2)\).
In our case, \(a = 4c\) and \(b = 1\). Apply the formula to the expression:
\((4c)^3 + (1)^3 = (4c + 1)((4c)^2 - (4c)(1) + (1)^2)\)
3Step 3: Expand and simplify
Now, we expand and simplify:
\((4c + 1)(16c^2 - 4c + 1)\)
So the factored form of the given expression is \((4c + 1)(16c^2 - 4c + 1)\).
Key Concepts
Sum of CubesAlgebraic ExpressionsFactoring Techniques
Sum of Cubes
The concept of the "sum of cubes" is a fundamental topic in algebra. It involves expressing a number or an expression as a sum of two cubed terms. The standard mathematical representation for the sum of cubes is shown as:
By recognizing that \(64c^3\) is \((4c)^3\) and \(1\) is \((1)^3\), we see that the problem can be rewritten using the sum of cubes formula. Thus, it becomes \((4c)^3 + (1)^3\).
This allows us to utilize specific algebraic formulas to split and manipulate the expression further. Understanding how to break down expressions into cubes is essential, as it simplifies solving complex polynomial equations in algebra.
- \(a^3 + b^3\)
By recognizing that \(64c^3\) is \((4c)^3\) and \(1\) is \((1)^3\), we see that the problem can be rewritten using the sum of cubes formula. Thus, it becomes \((4c)^3 + (1)^3\).
This allows us to utilize specific algebraic formulas to split and manipulate the expression further. Understanding how to break down expressions into cubes is essential, as it simplifies solving complex polynomial equations in algebra.
Algebraic Expressions
Algebraic expressions are the building blocks of algebra. They consist of variables, constants, and arithmetic operations. In essence, an algebraic expression is a combination of numbers and letters representing real-world quantities. The expression \(64c^3 + 1\) involves these elements:
- Coefficient \(64\): Multiplies the variable \(c^3\).
- Variable \(c\): Represents an unknown value, raised to the third power \(c^3\).
- Constant \(1\): An unchanging number added to the term.
Factoring Techniques
Factoring techniques are strategies used to decompose algebraic expressions into products of simpler expressions. Different patterns and formulas are used based on the expression's structure. The sum of cubes follows a specific formula:
- \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\)
- Set \(a = 4c\) and \(b = 1\).
- Applying the formula, \((4c)^3 + (1)^3\) becomes \((4c + 1)((4c)^2 - 4c \cdot 1 + 1^2)\).
- Expand to get: \((4c + 1)(16c^2 - 4c + 1)\).
Other exercises in this chapter
Problem 83
Find the indicated values for the following polynomial functions. $$h(k)=5 k^{3}-25 k^{2}+20 k .\( Find \)k\( so that \)h(k)=0$$
View solution Problem 83
Factor completely. You may need to begin by taking out the GCF first or by rearranging terms. $$42 k^{3}+15 d^{2}-18 k^{2} d-35 k d$$
View solution Problem 84
Factor completely. You may need to begin by taking out the GCF first or by rearranging terms. $$12 x^{3}+2 y^{2}-3 x^{2} y-8 x y$$
View solution Problem 84
Factor completely by first taking out a negative common factor. $$-6 x^{3}-54 x^{2}-48 x$$
View solution