Problem 84
Question
Explain why it is generally not necessary to take into account second or third ionization constants when calculating the \(\mathrm{pH}\) of a polyprotic acid solution.
Step-by-Step Solution
Verified Answer
The first ionization is dominant, and subsequent ionizations contribute negligibly.
1Step 1: Understanding Ionization Constants
Polyprotic acids have multiple ionizable hydrogen ions, each with its own ionization constant: the first ionization constant \(K_a1\), the second ionization constant \(K_a2\), and so on. The first ionization constant is significantly larger than the subsequent ones, meaning the first deprotonation occurs most readily.
2Step 2: First Ionization Dominance
Since \(K_a1\) is much larger than \(K_a2\) and \(K_a3\), the first ionization is the primary contributor to the hydrogen ion concentration in solution. The second and third ions have a much lower tendency to dissociate.
3Step 3: Negligible Contribution from Later Ionizations
The subsequent ionization constants are typically so small that their contribution to the hydrogen ion concentration is negligible. For example, in real scenarios \(K_a2\) is often five or more orders of magnitude smaller than \(K_a1\).
4Step 4: Simplification in Calculations
In \mathrm{pH}\ calculations, we often assume the concentration of hydrogen ions is dominated by the first ionization, allowing us to simplify calculations by only considering \(K_a1\). This results in a more straightforward calculation of \mathrm{pH}\.
Key Concepts
Ionization ConstantpH CalculationHydrogen Ion ConcentrationFirst Ionization Constant
Ionization Constant
Ionization constants are important in understanding how acids release their hydrogen ions during a chemical reaction. A polyprotic acid can release more than one hydrogen ion, and each of these releases has its own ionization constant, named as sequential constants:
- First ionization constant, denoted as \(K_{a1}\)
- Second ionization constant, denoted as \(K_{a2}\)
- Third ionization constant, denoted as \(K_{a3}\)
pH Calculation
In chemistry, calculating the pH of a solution is pivotal for understanding its acidity or alkalinity. pH is defined as the negative logarithm of the hydrogen ion concentration: \[ \text{pH} = -\log [\text{H}^+] \] For polyprotic acids, simplifying the pH calculation is crucial because these acids can release multiple hydrogen ions. However, due to the significant difference between the ionization constants, most of the hydrogen ions come from the first ionization. This allows chemists to use the following steps:
- Focus on the first ionization constant \(K_{a1}\).
- Use \(K_{a1}\) to calculate the primary hydrogen ion concentration \([\text{H}^+]\).
- Calculate pH based on this concentration.
Hydrogen Ion Concentration
The concentration of hydrogen ions \([\text{H}^+]\) in a solution is a key factor in determining its pH. In the context of polyprotic acids, determining this concentration is simplified by the dominance of the first ionization constant \(K_{a1}\). The larger value of \(K_{a1}\) implies that the dissociation of the first hydrogen ion is much more significant compared to subsequent dissociations. This results in a primary contribution to the \([\text{H}^+]\) concentration from the first ionization step. When calculating hydrogen ion concentration for such acids, chemists often assume:
- The concentration of hydrogen ions is approximately equal to that from the first dissociation alone.
- This approach is accurate because subsequent dissociations are negligible due to much smaller values of \(K_{a2}\) and \(K_{a3}\).
First Ionization Constant
The first ionization constant, \(K_{a1}\), is a crucial concept in understanding polyprotic acids. It reflects the strength and extent to which the first hydrogen ion is released in solution. The significance of \(K_{a1}\) lies in its relatively large value compared to \(K_{a2}\) and \(K_{a3}\), which means this first release is most impactful. Practically, this means:
- The first ionization generally dominates the behavior of polyprotic acids in solution.
- Subsequent ionizations have such small values that their effect can often be ignored during calculations to avoid unnecessary complexity.
- By assuming dominance of \(K_{a1}\), pH and hydrogen ion concentration calculations become straightforward and reliable.
Other exercises in this chapter
Problem 78
From the relationship \(K_{\mathrm{a}} K_{\mathrm{b}}=K_{\mathrm{w}},\) what can you deduce about the relative strengths of a weak acid and its conjugate base?
View solution Problem 83
Write all the species (except water) that are present in a phosphoric acid solution. Indicate which species can act as a Br?nsted acid, which as a Bronsted base
View solution Problem 85
Compare the pH of a \(0.040 \mathrm{M} \mathrm{HCl}\) solution with that of a \(0.040 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\) solution. (Hint: \(\mathrm{H}_
View solution Problem 86
What are the concentrations of \(\mathrm{HSO}_{4}^{-}, \mathrm{SO}_{4}^{2-}\), and \(\mathrm{H}_{3} \mathrm{O}^{+}\) in a \(0.20 \mathrm{M} \mathrm{KHSO}_{4}\)
View solution