Problem 84
Question
Determine whether the function is even, odd, or neither (a) algebraically, (b) graphically by using a graphing utility to graph the function, and (c) numerically by using the table feature of the graphing utility to compare \(f(x)\) and \(f(-x)\) for several values of \(x\). $$f(x)=x \sqrt{x+5}$$
Step-by-Step Solution
Verified Answer
The function \(f(x)=x \sqrt{x+5}\) is neither even nor odd.
1Step 1: Algebraic Analysis
Substitute \(x\) with \(-x\) in the equation: \(f(-x)=-x \sqrt{-x+5}\). This does not equal \(f(x)\), nor does it equal \(-f(x)\), which means the function is neither even nor odd algebraically.
2Step 2: Graphical Analysis
By graphing the function \(f(x)=x \sqrt{x+5}\), we can see that the graph doesn't display symmetry with respect to the y-axis or the origin. Therefore, the function is neither even nor odd graphically.
3Step 3: Numerical Analysis
Choose several values for \(x\) and calculate \(f(x)\) and \(f(-x)\). Comparing these values shows that \(f(x) \neq f(-x)\) and \(f(x) \neq -f(-x)\), supporting the conclusion that the function is neither even nor odd.
Key Concepts
Graphical AnalysisNumerical AnalysisAlgebraic Analysis
Graphical Analysis
Understanding whether a function is even or odd through graphical analysis involves observing the symmetry of its graph.
The function's graph is plotted, and key symmetries are examined:
For the function \[f(x) = x \sqrt{x+5}\], examining the graph shows neither y-axis symmetry nor origin symmetry.
This confirms graphically that the function is neither even nor odd.
The function's graph is plotted, and key symmetries are examined:
- An even function has symmetry about the y-axis.
- An odd function has rotational symmetry around the origin.
For the function \[f(x) = x \sqrt{x+5}\], examining the graph shows neither y-axis symmetry nor origin symmetry.
This confirms graphically that the function is neither even nor odd.
Numerical Analysis
Numerical analysis involves evaluating the function at multiple points to understand its behavior better.
This step allows us to compare the values of \(f(x)\) and \(f(-x)\):
For example, testing a few points on the function \(f(x) = x \sqrt{x+5}\), such as \(x=0\), \(x=1\), and \(x=-1\), confirms that neither condition fits. Thus, numerically, the function is neither even nor odd.
This step allows us to compare the values of \(f(x)\) and \(f(-x)\):
- If \(f(x) = f(-x)\) for all \(x\), the function is even.
- If \(f(x) = -f(-x)\) for all \(x\), the function is odd.
- If neither condition is satisfied, the function is neither.
For example, testing a few points on the function \(f(x) = x \sqrt{x+5}\), such as \(x=0\), \(x=1\), and \(x=-1\), confirms that neither condition fits. Thus, numerically, the function is neither even nor odd.
Algebraic Analysis
To determine the nature of the function algebraically, we substitute \(x\) with \(-x\) in \(f(x)\):
\[ f(-x) = -x \sqrt{-x+5} \]
Comparing, neither \(f(-x) = f(x)\) nor \(f(-x) = -f(x)\) holds.
This result indicates that the function is neither even (no y-axis symmetry) nor odd (no origin symmetry) algebraically.
Algebraic analysis confirms why neither type of symmetry exists for this specific function.
\[ f(-x) = -x \sqrt{-x+5} \]
Comparing, neither \(f(-x) = f(x)\) nor \(f(-x) = -f(x)\) holds.
This result indicates that the function is neither even (no y-axis symmetry) nor odd (no origin symmetry) algebraically.
Algebraic analysis confirms why neither type of symmetry exists for this specific function.
Other exercises in this chapter
Problem 83
Identify any relationships that exist among the lines, and then use a graphing utility to graph the three equations in the same viewing window. Adjust the viewi
View solution Problem 84
Find the domain of the function.$$f(x)=\frac{\sqrt{x-5}}{x-7}$$
View solution Problem 84
Find the difference quotient and simplify your answer. $$g(x)=3 x-1, \frac{g(x+h)-g(x)}{h}, \quad h \neq 0$$
View solution Problem 84
Identify any relationships that exist among the lines, and then use a graphing utility to graph the three equations in the same viewing window. Adjust the viewi
View solution