Problem 83
Question
What are (a) \(K,(\) b) \(E\), and \((\mathrm{c}) p(\) in \(\mathrm{GeV} / c)\) for a proton moving at speed \(0.990 c\) ? What are (d) \(K\), (e) \(E\), and (f) \(p\) (in \(\mathrm{MeV} / c\) ) for an electron moving at speed \(0.990 c ?\)
Step-by-Step Solution
Verified Answer
For the proton: (a) \(K = 6.064\text{ GeV}\), (b) \(E = 6.646\text{ GeV}\), (c) \(p = 6.640\text{ GeV/c}\). For the electron: (d) \(K = 3.797\text{ MeV}\), (e) \(E = 3.808\text{ MeV}\), (f) \(p = 3.796\text{ MeV/c}\).
1Step 1: Identify the Known Values
For a proton, mass is \( 938 \) MeV/c², and for an electron, mass is \( 0.511 \) MeV/c². In both scenarios, speed \( v = 0.990c \).
2Step 2: Calculate Lorentz Factor \( \gamma \)
The Lorentz factor \( \gamma \) is given by:\[ \gamma = \frac{1}{\sqrt{1 - \left(\frac{v}{c}\right)^2}} \]Substituting \( v = 0.990c \):\[ \gamma = \frac{1}{\sqrt{1 - (0.990)^2}} \approx 7.088 \]
3Step 3: Calculate Kinetic Energy \( K \) for Proton and Electron
Kinetic energy for relativistic speeds is \( K = (\gamma - 1)mc^2 \).For the proton:\[ K_p = (7.088 - 1) \times 938 \text{ MeV} \approx 6064 \text{ MeV} = 6.064 \text{ GeV} \]For the electron:\[ K_e = (7.088 - 1) \times 0.511 \text{ MeV} \approx 3.797 \text{ MeV} \]
4Step 4: Calculate Total Energy \( E \) for Proton and Electron
The total energy is \( E = \gamma mc^2 \).For the proton:\[ E_p = 7.088 \times 938 \text{ MeV} \approx 6646 \text{ MeV} = 6.646 \text{ GeV} \]For the electron:\[ E_e = 7.088 \times 0.511 \text{ MeV} \approx 3.808 \text{ MeV} \]
5Step 5: Calculate Momentum \( p \) for Proton and Electron
The momentum is \( p = \gamma mv \).Since \( p \) is often expressed per \( c \), use \( p = \gamma mv/c \). For the proton:\[ p_p = 7.088 \times 938 \text{ MeV/c}^2 \times 0.990c / c \approx 6640 \text{ MeV/c} = 6.640 \text{ GeV/c} \]For the electron:\[ p_e = 7.088 \times 0.511 \text{ MeV/c}^2 \times 0.990c / c \approx 3.796 \text{ MeV/c} \]
Key Concepts
Understanding the Lorentz FactorExploring Kinetic Energy at Relativistic SpeedsCalculating Total Energy for Fast-Moving ParticlesThe Role of Momentum in RelativityWhy Focus on the Proton?Understanding Electron SpeedWhat Are Relativistic Speeds?
Understanding the Lorentz Factor
The Lorentz factor (\( \gamma \)) is crucial in relativity when objects approach the speed of light (c). It relates the observed length, time, and energy from different inertial frames.
- Formula: \[ \gamma = \frac{1}{\sqrt{1 - \left( \frac{v}{c} \right)^2 }} \]
- Importance: As speed increases towards the speed of light, the Lorentz factor becomes significantly greater than one.
- At high speeds, it affects how we measure time (time dilation), length (length contraction), and energy.
Exploring Kinetic Energy at Relativistic Speeds
Kinetic energy (\(K\)) at relativistic speeds diverges from classical mechanics. In classical physics, \(K\ = \frac{1}{2}mv^2\). However, when objects move close to light speed, we use:\[ K = (\gamma - 1) mc^2 \]Key points:
- Kinetic energy increases substantially at relativistic speeds.
- This equation accounts for energy increases due to inertia growth at high speeds.
Calculating Total Energy for Fast-Moving Particles
The total energy (\(E\)) of an object is the sum of its rest mass energy and its kinetic energy. When dealing with relativistic speeds, it's crucial to use:\[ E = \gamma mc^2 \]
- Total energy grows with speed due to increases in both mass and kinetic energy.
- In the exercise, for the proton, we calculate total energy to be around 6.646 GeV.
- For the electron, total energy is about 3.808 MeV.
The Role of Momentum in Relativity
Momentum (\(p\)) in relativity differs significantly from its classical counterpart. In relativistic contexts, it's given by:\[ p = \gamma mv \]
- The factor \(\gamma\) accounts for velocity increases near the speed of light.
- This equation shows momentum is not just dependent on speed, but also on relativistic mass.
Why Focus on the Proton?
Protons are subatomic particles found in atomic nuclei. They are often used in particle physics due to their charge and relatively large mass:
- Mass: 938 MeV/c²
- Application: Protons are a primary subject in particle collisions and high-energy physics experiments.
Understanding Electron Speed
Electrons, while much lighter than protons with a mass of 0.511 MeV/c², play a critical role in atomic and subatomic physics. Their speed can greatly influence calculations at high velocities:
- Mass: 0.511 MeV/c²
- Behavior: Lightness means that relativistic effects, such as kinetic energy, are proportionally less than for protons.
What Are Relativistic Speeds?
Relativistic speeds refer to velocities close to the speed of light. At these speeds, classical Newtonian mechanics is no longer sufficient to describe motion:
- Effects: Objects appear heavier and time slows down, a phenomenon explained by Einstein's theory of relativity.
- The exercise indicates: With both protons and electrons moving at 0.990c, relativistic calculations are necessary.
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