Problem 83
Question
Use a graphing calculator to plot \(y=\ln (2 x)\) and \(y=\ln 2+\ln x .\) Are they the same graph?
Step-by-Step Solution
Verified Answer
Yes, they are the same graph.
1Step 1: Understanding the Functions
The functions given are \( y = \ln(2x) \) and \( y = \ln 2 + \ln x \). We need to determine if these represent the same mathematical relationship.
2Step 2: Applying Logarithm Properties
Use the logarithm property \( \ln(ab) = \ln a + \ln b \) to transform \( \ln(2x) \). According to this property, \( \ln(2x) = \ln 2 + \ln x \).
3Step 3: Simplifying the Functions
Since \( \ln(2x) = \ln 2 + \ln x \) algebraically simplifies to \( y = \ln 2 + \ln x \), these two expressions are mathematically equivalent under the property of logs.
4Step 4: Confirming with a Graphing Calculator
Plot both functions \( y = \ln(2x) \) and \( y = \ln 2 + \ln x \) on a graphing calculator. Check if the graphs overlap completely to confirm their equivalence.
5Step 5: Conclusion
As both functions simplify to the same expression and their graphs overlap exactly, they represent the same graph.
Key Concepts
Properties of LogarithmsGraphing CalculatorsMathematical Equivalence
Properties of Logarithms
Logarithmic functions have specific properties that simplify complex expressions. These properties make calculations involving logarithms much easier. Let's focus on a key property used in our exercise: the product property.
The product property of logarithms states that \( \ln(ab) = \ln a + \ln b \). This means, when you have a logarithm of a product, you can break it into a sum of logarithms.
In the exercise, we used this property to show that \( \ln(2x) = \ln 2 + \ln x \). By applying this property, the original expression is simplified, highlighting the mathematical equivalence of the two expressions.
The product property of logarithms states that \( \ln(ab) = \ln a + \ln b \). This means, when you have a logarithm of a product, you can break it into a sum of logarithms.
In the exercise, we used this property to show that \( \ln(2x) = \ln 2 + \ln x \). By applying this property, the original expression is simplified, highlighting the mathematical equivalence of the two expressions.
- This property is essential for understanding how seemingly different looking expressions can actually represent the same function.
- It helps tremendously in simplifying and solving logarithmic equations.
Graphing Calculators
Graphing calculators are crucial tools for visualizing mathematical concepts. They allow us to plot equations and observe their graphical behavior. In the context of logarithmic functions, they are especially valuable.
By plotting the functions \( y = \ln(2x) \) and \( y = \ln 2 + \ln x \), a graphing calculator can visually confirm their equivalence.
When you input these equations into a graphing calculator:
By plotting the functions \( y = \ln(2x) \) and \( y = \ln 2 + \ln x \), a graphing calculator can visually confirm their equivalence.
When you input these equations into a graphing calculator:
- You'll see both graphs appear on the screen.
- If the graphs overlap completely, it confirms that the functions are equivalent.
Mathematical Equivalence
Mathematical equivalence is a fundamental concept indicating that two expressions represent the same value. In the exercise, determining the equivalence of \( \ln(2x) \) and \( \ln 2 + \ln x \) illustrates this principle.
Using the property of logarithms, we showed their algebraic equivalence, which is crucial for solving equations and validating solutions.
Equivalence means:
Using the property of logarithms, we showed their algebraic equivalence, which is crucial for solving equations and validating solutions.
Equivalence means:
- The expressions hold true across all values within a given domain.
- They can be used interchangeably, meaning solving one gives the same result as solving the other.
Other exercises in this chapter
Problem 82
Find the \(y\) -intercept and horizontal asymptote(s) of \(f(x)=2^{x}+3^{x}\)
View solution Problem 82
Graph the logarithmic function using transformation techniques. State the domain and range of \(f\). $$f(x)=\ln (4-x)$$
View solution Problem 83
Plot the function \(y=\left(1+\frac{1}{x}\right)^{x} .\) What is the horizontal asymptote as \(x\) increases?
View solution Problem 83
Graph the logarithmic function using transformation techniques. State the domain and range of \(f\). $$f(x)=\log (2 x)$$
View solution